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3 years ago

Louie has two jobs and can work no more than 25 total

Mathematics

1 answer:

zubka84 [21]3 years ago

4 0

If he works for 12.5 hours a week at one job he will have more than $150 in a week.

as a busboy, he will earn $81.25

and as a clerk, he will earn, $100 if he works for 12.5 hours a week which is $181 a week.

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The sum of numbers is 28. the difference of two numbers is -2. find the numbers

Vesna [10]

I believe 15 and 13. 13-15=-2 and added is 28....?

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3 years ago

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Remy walked to a friend’s house m miles away at an average rate of 4 mph. The m-mile walk home was at only 3 mph, however. Expre

WARRIOR [948]

Answer:

sorry if im rong b

Step-by-step explanation:

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3 years ago

Melanie uses 8.1 pints of blue paint and white paint to paint her bedroom walls. 2/5 of this amount is blue paint, and the rest

attashe74 [19]

Answer:

4.86

Step-by-step explanation:

Melanie uses 8.1 pints of blue paint and white paint for her bedroom

2/5 of this amount is blue paint

Therefore the amount of white paint can be calculated as follows

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= 0.4×100

= 40%

60/100 × 8.1

= 0.6 × 8.1

= 4.86

Hence 4.86 pints of white paint will be used to paint the bedroom

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3 years ago

Give this problem a try and try to solve this

tia_tia [17]

Answer:

No solution

Step-by-step explanation:

Given equation is,

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}-\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}=0$

$\frac{x^{\frac{1}{2}}+x^{-\frac{1}{2}}}{1-x}+\frac{1-x^{-\frac{1}{2}}}{1+x^\frac{1}{2}}=\frac{(4+x)^\frac{1}{2}}{(1-x)^\frac{1}{2}}$

$\frac{(x+1)}{\sqrt{x}(1-x)}+\frac{(\sqrt{x}-1)}{\sqrt{x}(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{(\sqrt{x}+1)(x+1)+(\sqrt{x}-1)(1-x)}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^{\frac{1}{2}}$

$\frac{x\sqrt{x}+x+\sqrt{x}+1+\sqrt{x}-1-x\sqrt{x}+x}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2x+2\sqrt{x}}{\sqrt{x}(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2(\sqrt{x}+1)}{(1-x)(1+\sqrt{x})}=(\frac{4+x}{1-x})^\frac{1}{2}$

$\frac{2}{1-x}=(\frac{4+x}{1-x})^\frac{1}{2}$ if x ≠ ±1

$(\frac{2}{1-x})^2=\frac{4+x}{1-x}$ [Squaring on both the sides of the equation]

$\frac{4}{(1-x)}=(4+x)$

4 = (1 - x)(4 + x)

4 = 4 - 4x + x - x²

0 = -3x - x²

x² + 3x = 0

x(x + 3) = 0

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But both the solutions x = 0 and x = -3 are extraneous solutions, given equation has no solution.

5 0

4 years ago

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29.87 × 1.089 show work

ankoles [38]

52.22583 srry I couldn’t show work I was In a hurry to go somewhere

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3 years ago