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kow [346]
3 years ago
11

This is my last question and I don’t want to mess up this test this is my final question

Mathematics
1 answer:
n200080 [17]3 years ago
6 0

Answer:

y = 8.9

Step-by-step explanation:

according to pythagorus theorem,

p {}^{2}  = h {}^{2}  - b {}^{2}

( where p = perpendicular, b = base and

h = hypotenuse )

so,

=》

y {}^{2}  = 12 {}^{2}  - 8 {}^{2}

=》

y {}^{2}  = 144 - 64

=》

y {}^{2}  = 80

=》

y =  \sqrt{80}

=》

y = 8.9

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em><em>.</em>

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3 years ago
What's 4/5 as a decimal. Thank you. :)
vesna_86 [32]

Answer: .8


Step-by-step explanation: 4/5 = .8



7 0
3 years ago
Read 2 more answers
Given sintheta =7/11 and sectheta is less than 0, find costheta and tantheta
Korvikt [17]

Answer:

Step-by-step explanation:

Sin theta is the ratio of side opposite over hypotenuse of a reference angle situated at the origin in an x-y coordinate plane.  If sec theta is negative, then the only quadrant where sin is positive AND sec is negative is quadrant 2.  Remember that sec theta is the inverse of cos theta.  Puttling our right triangle in QII, the side measuring 7 is across from the angle and the hypotenuse is 11.  In order to find the cos theta and tan theta, we need the side adjacent to the angle.  Use Pythagorean's Theorem to find the side adjacent.

11^2=7^2+x^2 and

121=47+x^2 and

72=x^2 so

x=6\sqrt{2}

Remember that this value is why the sec is negative.  Because x is negative in QII, the cos theta is side adjacent over hypotenuse:

cos\theta=-\frac{6\sqrt{2} }{11}  and

tan\theta=-\frac{7}{6\sqrt{2} }

But we should probably rationalize that denominator, so

tan\theta=-\frac{7}{6\sqrt{2} }*\frac{\sqrt{2} }{\sqrt{2} } =-\frac{7\sqrt{2} }{12}

5 0
3 years ago
If the area of the vegetable garden is 170 square feet which equation could be of use to find the length of the tomato patch? 0=
Semmy [17]

Answer:

The equation 0 = 3x² + 17x - 160 could be of use in finding the length.

Step-by-step explanation:

We are told that the area of the vegetable garden is 170 ft².

Now, from the options;

1) For 0 = 3x² + 2x + 180, using quadratic formula, we have:

x = [-2 ± √(3² - 4(3 × 180)]/(2 × 3)

x = [-2 ± √(-2151)]/6

The value inside the square root is negative, thus there is no natural root of x.

Hence, the equation can't be used to find the length.

2) For the equation 0 = 3x² + 10x + 180, using quadratic formula, the value inside the square root would also be negative and as such there is no natural root of x. So this equation can't be used to get the length.

3) For the equation 0 = 3x² + 17x - 160, using quadratic formula, the roots are -10.67 or 5. We can use 5 as it's a whole number. Since the area is also a whole number, then this equation can be used to find the length.

4) For the equation 0 = 3x² - 160, simplifying, we have;

3x² = 160

x² = 160/3

x = ±√(160/3)

x = ±7.303

Since area is a whole number and this length is not, this equation may not be an accurate way to get the length.

5 0
3 years ago
Sum of 3 by 4 and 7 by 4 is ___​
denpristay [2]

Step-by-step explanation:

Sum of 3 by 4 and 7 by 4 is

=  \frac{3}{4}  +  \frac{7}{4 }  \\  =  \frac{3 + 7}{4}  \\  =  \frac{10}{4}  \\  =  \frac{5}{2}

Hope it will help :)

3 0
3 years ago
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