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maksim [4K]
1 year ago
6

Use the distribution property to explain how 30 flowers in a bunch can be counted in groups of 2s and 3s.

Mathematics
1 answer:
Shtirlitz [24]1 year ago
8 0

The way 30 flowers in a bunch can be counted in groups of 2s and 3s is 2(3(3) + 3(2))

<h3>Prime factorization of numbers</h3>

From the question, the interpretation is that we are to write the prime factorization of 30

30 = 2 * 15

30 = 2{3 (3 + 2)}

Expand using the distribution property

30 = 2(3(3) + 3(2))

30 = 2(9 + 6)

Hence the way 30 flowers in a bunch can be counted in groups of 2s and 3s is 2(3(3) + 3(2))

Learn more on prime factorization here: brainly.com/question/92257

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HEY YA'LL 30 PTS FOR 1 PROBLEM!<br> Given: m∠EYL=1/3 the measure of arc EHL<br> Find: m∠EYL.
GarryVolchara [31]

Answer:

45

Step-by-step explanation:

Two tangents drawn to a circle from an outside point form arcs and an angle, and this formula shows the relation between the angle and the two arcs.

m<EYL = (1/2)(m(arc)EVL - m(arc)EHL)      Eq. 1

The sum of the angle measures of the two arcs is the angle measure of the entire circle, 360 deg.

m(arc)EVL + m(arc)EHL = 360

m(arc)EVL = 360 - m(arc)EHL      Eq. 2

We are given this:

m<EYL = (1/3)m(arc)EHL       Eq. 3

Substitute equations 2 and 3 into equation 1.

(1/3)m(arc)EHL = (1/2)[(360 - m(arc)EHL) - m(arc)EHL]

Now we have a single unknown, m(arc)EHL, so we solve for it.

2m(arc)EHL = 3[360 - m(arc)EHL - m(arc)EHL]

2m(arc)EHL = 1080 - 6m(arc)EHL

8m(arc)EHL = 1080

m(arc)EHL = 135

Substitute the arc measure just found in Equation 3.

m<EYL = (1/3)m(arc)EHL

m<EYL = (1/3)(135)

m<EYL = 45

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Answer:

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sorry if i am incorrect.

Step-by-step explanation:

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Step-by-step explanation:

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33.3% is the answer, I think

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