Answer:
C
Step-by-step explanation:
(x+2)² + (y-3)² = 3²
x² + y² + 4x - 6y + 4 + 9 - 9 = 0
x² + y² + 4x - 6y + 4 = 0
The weight of the hamburger is 160g after two bites.
Each bite takes away 20% of the weight of the burger, so we'll divide the initial weight by a percentage to find the weight before the bite.
The starting weight is 160g. Because 20% of the weight was removed from a bite, we'll divide this weight by the percentage of the burger remaining after the bite:

80% of the burger is left after a bite. Convert this fraction into a decimal by dividing by 100:

Divide the initial weight by this decimal:

The weight of the burger before the second bite was 200.
We'll do the same procedure for the first bite. The initial weight is 200, and there is 80% of the burger remaining after the first bite. Because 80% is 0.8 in decimal form, divide 200 by 0.8:

The starting weight of the burger before the bites was
250 grams.
Answer:
54 can be divided into 45 and 9
Step-by-step explanation:
add 1+5=6
therefore 1/6*54=9
5/6*54=45
Step-by-step explanation:
x + y = 9. => 2x + 2y = 18.
2x + 2y = 18
- (2x - 3y = -12)
=> 5y = 30, y = 6.
Therefore x + (6) = 9, x = 3.
The solution is x = 3 and y = 6.