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Dafna1 [17]
3 years ago
14

Assessment

Chemistry
1 answer:
Lilit [14]3 years ago
5 0

Answer:

how do i calculate that?tell me how and i will try to do your math

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In monostremes the placenta absors oxygen and food from the mothers blood.
Mandarinka [93]
This is a statement. 
8 0
4 years ago
What is the complementary DNA sequence for C G T T A C C G in chargaff's rule?
djverab [1.8K]

Answer:

Chargaff's rule, also known as the complementary base pairing rule, states that DNA base pairs are always adenine with thymine (A-T) and cytosine with guanine (C-G). A purine always pairs with a pyrimidine and vice versa. However, A doesn't pair with C, despite that being a purine and a pyrimidine.

Explanation:

In these nucleotides, there is one of the four possible bases: adenine (A), guanine (G), cytosine (C), or thymine (T) (Figure below). Adenine and guanine are purine bases, and cytosine and thymine are pyrimidine bases. Chemical structure of the four nitrogenous bases in DNA✔✔

8 0
3 years ago
Suppose 2.8 moles of methane are allowed to react with 5 moles of oxygen.
Ronch [10]

Answer : The limiting reagent is O_2

Solution : Given,

Moles of methane = 2.8 moles

Moles of O_2 = 5 moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 5 moles of O_2 react with \frac{5}{2}=2.5 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Hence, the limiting reagent is O_2

8 0
4 years ago
Calculate either [H3O+] or [OH−] for each of the solutions at 25 °C. Solution A: [OH−]=1.55×10−7 M Solution A: [H3O+]= M Solutio
Ahat [919]

Answer: A. [H_3O^+]=0.64\times 10^{-7}M

B. [OH^-]=0.11\times 10^{-5}M

C. [OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M

Thus solution B is basic in nature.

Explanation:

pH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH for acidic solutions is less than 7, for basic solutions it is more than 7 and for neutral solutions it is equal to 7.

pH=-\log [H^+]

pOH=-log[OH^-]

pH+pOH=14

or [H^+][OH^-]=10^{-14}

A. [OH^-]=1.55\times 10^{-7}M

[H_3O^+]=\frac{10^{-14}}{1.55\times 10^{-7}}=0.64\times 10^{-7}M

pH=-log[H_3O^+]=-log[0.64\times 10^{-7}]=7

B. [H_3O^+]=9.43\times 10^{-9}M

[OH^-]=\frac{10^{-14}}{9.43\times 10^{-9}}=0.11\times 10^{-5}M

pH=-log[H_3O^+]=-log[9.43\times 10^{-9}]=8

C. [H_3O^+]=0.000775M

[OH^-]=\frac{10^{-14}}{0.000775}=1.3\times 10^{-11}M

pH=-log[H_3O^+]=-log[0.000775]=3

Thus solution B is basic.

4 0
4 years ago
Which of the four containers represents a compound?<br> A) Cl <br> B) H2O <br> C) N2 <br> D) Na
MissTica
B)H20 Hydrogen+oxygen=H2O
(Water) you should know this
6 0
3 years ago
Read 2 more answers
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