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Dafna1 [17]
3 years ago
14

Assessment

Chemistry
1 answer:
Lilit [14]3 years ago
5 0

Answer:

how do i calculate that?tell me how and i will try to do your math

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HELP PLZ!CHEMISTRY.WILL GIVE BRAINLIEST!!!!
Andrej [43]

1. 12 L = 12 dm³

2. 3.18 g

<h3>Further explanation</h3>

Given

1. Reaction

K₂CO₃+2HNO₃⇒ 2KNO₃+H₂O+CO₂

69 g K₂CO₃

2. 0.03 mol/L Na₂CO₃

Required

1. volume of CO₂

2. mass Na₂CO₃

Solution

1. mol K₂CO₃(MW=138 g/mol) :

= 69 : 138

= 0.5

mol ratio of K₂CO₃ : CO₂ = 1 : 1, so mol CO₂ = 0.5

Assume at RTP(25 C, 1 atm) 1 mol gas = 24 L, so volume CO₂ :

= 0.5 x 24 L

= 12 L

2. M Na₂CO₃ = 0.03 M

Volume = 1 L

mol Na₂CO₃ :

= M x V

= 0.03 x 1

= 0.03 moles

Mass Na₂CO₃(MW=106 g/mol) :

= mol x MW

= 0.03 x 106

= 3.18 g

3 0
3 years ago
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Explanation:

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Which temperature represents the highest average kinetic energy of the particles in a sample of matter?
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Answer:

41 Which temperature represents the highest average kinetic energy of the particles in a sample of matter? (1) 298 K (3) 27°C (2) 267 K (4) 12°C

Explanation:

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3 years ago
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