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3 years ago

Please help, thanks!

Chemistry

1 answer:

Anastasy [175]3 years ago

5 0

You need to use the formula--> P1V1= P2V2 (Boyles's law)

P1= 14 bar
V1= 312 mL
P2= ?
V2= 652 mL

now we plug the values into the formula.

(14 x 312) = (P2x 652)

P2= (14 x 312)/ 652= 6.70 bar

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How many moles of N2 are found in 3.5 L?

ella [17]

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles N2, or 28.0134 grams.

Explanation:

3 0

3 years ago

How much volume would a 834.01g pile of sugar have given that it has a density of 1.59g/mL?

boyakko [2]

Answer:

v = 534.5mL

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Explanation:

Density = mass/ volume

For the first question

Density = 1.59g/mL

Mass = 834.01g

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Using the above formula we have 1.59 = 834.01/v

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Using the above formula we have

0.9167 =m/651.41

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m = 0.9167 x 651.41

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7 0

4 years ago

An element has three naturally occurring isotopes. ten percent (.10) occurs as 55^x, fifteen percent (.15) occurs as isotope 56^

Leviafan [203]

The average atomic weight is, from the name itself, the average weight of all its naturally occurring isotopes. All you have to do is multiple the abundance of each isotope with its individual mass, then add them altogether.

Mass = (0.10*55)+(0.15*56)+(.75*57)
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4 years ago

The particles of a gas are O electrons O atoms or molecules O neutrons O waves

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Answer:
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Explanation:
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2 years ago

In which of the following compounds does the carbonyl stretch in the IR spectrum occur at the lowest wavenumber?

klio [65]

Answer:

a. Cyclohexanone

Explanation:

The principle of IR technique is based on the vibration of the bonds by using the energy that is in this region of the electromagnetic spectrum. For each bond, there is a specific energy that generates a specific vibration. In this case, you want to study the vibration that is given in the carbonyl group C=O. Which is located around 1700 cm-1.

Now, we must remember that the lower the wavenumber we will have less energy. So, what we should look for in these molecules, is a carbonyl group in which less energy is needed to vibrate since we look for the molecule with a smaller wavenumber.

If we look at the structure of all the molecules we will find that in the last three we have heteroatoms (atoms different to carbon I hydrogen) on the right side of the carbonyl group. These atoms allow the production of resonance structures which makes the molecule more stable. If the molecule is more stable we will need more energy to make it vibrate and therefore greater wavenumbers.

The molecule that fulfills this condition is the cyclohexanone.

See figure 1

I hope it helps!

4 0

4 years ago