The asymptotes are where the graph is undefined. Since: tan(x) =sin(x)/cos(x)
It is where cos(4x-π) = 0
cos(4x-π) = 0 when the inside is -π/2 , π/2 , 3π/2
4x - π = π/2
4x = π/2 + π
4x = 3π/2
x = 3π/8
4x - π = 3π/2
4x = 3π/2 + π
4x = 5π/2
x = 5π/8
This ones outside the interval (5π/8 > π/2) , try -π/2
4x - π = -π/2
4x = -π/2 + π
4x = π/2
x = π/8
Asymptotes are π/8 and 3π/8
Answer: Yes, a triangle can have sides of those lengths.
Step-by-step explanation:
<span>a.
The radius of earth is about 6400 kilometers. Find the circumference of
a great circle.
Circumference = 2π(radius) = 2π(6400 km) = 40.212,39 km
b. Write an equation for the circumference of any
latitude circle with angle theta
As stated, </span><span><span>the
length of any parallel of latitude (this is the circumference of corresponding circle) is equal to the circumference of a
great circle of Earth times the cosine of the latitude angle</span>:
=> Circumference = 2π*radius* cos(Θ) = 2 π*6400km*cos(Θ) = 40,212.39 cos(Θ)
Answer: circumference = 40,212.39 cos(Θ) km
c. Which latitude circle has a
circumference of about 3593 kilometers?
Make </span><span><span>40,212.39 cos(Θ)</span> km = 3593 km
=> cos(Θ) = 3593 / 40,212.39 = 0.08935 => Θ = arccos(0.08935) = 84.5° = 1.48 rad
Answer: 1.48
d. What is the circumference of
the Equator?
</span>
For the Equator Θ = 0°
=> circumference = 40,213.49cos(0°) km = 40,212.49 km
Answer: 40,212.49 km
the answer is b. 30 hope this helps
