Answer:
can't see the equation sorry
Let x and y be the two integers.
The sum of the integers is x+y while the difference is x-y assuming x is larger than y.
If x+y > x-y, then
x+y > x-y
x+y-x > x-y-x
y > -y
y+y > -y+y
2y > 0
2y/2 > 0/2
y > 0
So as long as y is positive, this makes the sum greater than the difference
For example, if x = 10 and y = 2, then
x+y = 10+2 = 12
x-y = 10-2 = 8
clearly 12 > 8 is true
If y is some negative number (say y = -4), then
x+y = 10+(-4) = 10-4 = 6
x-y = 10-(-4) = 10+4 = 16
and things flip around
Saying a blanket statement "the sum of two integers is always greater than their difference" is false overall. If you require y to be positive, then it works but as that last example shows, it doesn't always work.
So to summarize things up, I'd say the answer is "no, the statement isn't true overall"
Around $634.85 per year
Because:
$32.85+$35(12 months)+$3.5(52 weeks in a year)= Total cost per year
$420 $182
$32.85 + $420 + $182 = $634.85 per year
N= number of tickets purchased= 5 people went to the movies
t= cost of each ticket
$55.50 - $29.25= n * t
$55.50 - $29.25= 5t
OR
$55.50= 5t + $29.25
ANSWER: $55.50 - $29.25= 5t OR
$55.50= 5t + $29.25 (there were no equations to choose from, but it should look something like one of these).
Hope this helps! :)
