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scoundrel [369]
2 years ago
10

1. Write the equation of the line parallel to y = 7x – 5 and going through the point (4,31).

Mathematics
1 answer:
densk [106]2 years ago
6 0

Answer:

y=7x+3

Step-by-step explanation:

Hi there!

We are given the equation y=7x-5 and we want to find the equation of the line that is parallel to it, and contains the point (4,31)

First, let's find the slope of y=7x-5, since parallel lines have the same slopes

The line y=7x-5 is written slope-intercept form, which is y=mx+b, where m is the slope and b is the y intercept

Since 7 is in the place of where m is, the slope of the line is 7

It's also the slope of the line parallel to it.

We can substitute 7 as m into the formula y=mx+b for our new line:

y=7x+b

Now we need to find b

Since the equation will pass through the point (4, 31), we can use it to solve for b; substitute 31 as y and 4 as x

31=7(4)+b

Multiply

31=28+b

Subtract 28 from both sides

3=b

Substitute 3 as b

y=7x+3

Hope this helps!

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Step-by-step explanation:

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Answers: Angle A is 36 degrees, angle C is 54 degrees

=================================================================

Work Shown:

The angles A and C are complementary, meaning they add to 90 degrees.

(Angle A) + (Angle C) = 90

(2x-4) + (2x+14) = 90

(2x+2x)+(-4+14) = 90

4x+10 = 90

4x+10-10 = 90-10 .... subtract 10 from both sides

4x = 80

4x/4 = 80/4 ..... divide both sides by 4

x = 20

If x = 20, then,

angle A = 2x-4 = 2*20-4 = 40-4 = 36 degrees

angle C = 2x+14 = 2*20+14 = 40+14 = 54 degrees

Note how A+C = 36+54 = 90 which helps confirm our answers.

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