QUESTION 12
The given figure has five unequal sides.
The perimeter is the distance around the figure.
So we add all the lengths of the sides of the rectangle to get,

We regroup the like terms to obtain,

This will simplify to give us,


QUESTION 13
The given figure has two pairs of sides that are equal in length and three unequal sides.
The perimeter can be found by adding all the lengths of the sides of the of the figure.
This will give us

We regroup like terms to obtain,

This finally simplifies to ,
.

QUESTION 14
This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.
We add all the lengths of the sides of the plane figure to get,

This will simplify to give us,
Your answer is A. If we find the slope of the line and draw it out farther, we can see that the points 4,7,10, and 13 would fall on that line.
So ASA is angle side angle, and that means that if you prove that the side, and the side adjacent to that side and the angle between those two sides are all congruent to another triangle's sides and angle, the triangles are both congruent.
The AAS is angle angle side, or something, so say you have a triangle and you prove that two of its angles are congruent along with a side to another triangle's, then it's AAS. I understand where the confusion might be. I guess it's just a matter of what you state first in your proof?