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Sunny_sXe [5.5K]
3 years ago
6

Cost of boots: $99.99 Markup: 9% What is the new cost

Mathematics
1 answer:
mote1985 [20]3 years ago
6 0

Answer:

The new cost is $108.98

Step-by-step explanation:

Mark up is the amount that is added to cost price of a product for profit.

Given

Cost price of boots = C = $99.99

Mark up = 9%

First of all we will calculate markup and then add it to the cost price of boots to find the new cost.

Mark\ up = M = 9\%\ of\ 99.99\\= 0.09*99.99\\=\$8.99

The new cost will be:

C_n = Cost\ price + mark\ up\\C_n = 99.99+8.99\\= 108.98

The new cost is $108.98

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Rewrite the following as a decimal<br> -5 1/11
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A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
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Answer:

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

p_v =2*P(z>1.413)=0.158  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

Step-by-step explanation:

Data given and notation  

\bar X=5.0611 represent the sample mean

\sigma=0.2803 represent the population standard deviation for the sample  

n=42 sample size  

\mu_o =5 represent the value that we want to test

\alpha=0.1 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 5, the system of hypothesis would be:  

Null hypothesis:\mu = 5  

Alternative hypothesis:\mu \neq 5  

If we analyze the size for the sample is > 30 but and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{5.0611-5}{\frac{0.2803}{\sqrt{42}}}=1.413    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z>1.413)=0.158  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can't conclude that the average tensile strength is different from 5lbs/mm at 10% of signficance

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