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3 years ago

(9y+6)+(y+3) Add. Please help

Mathematics

1 answer:

Levart [38]3 years ago

5 0

(9y+y) + (6+3)
The answer is 10y+9

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Identify the vertex of the graph. Tell whether it is a minimum or maximum.

kolezko [41]

Answer: (-2, -2) minimum

Step-by-step explanation: since the graph is going upwards and the arch of the graph is the lowest point in the graph, it will be a minimum point. to find this minimum point, look at what point the lowest point of the graph (for this graph, it is (-2, -2) )

4 0

2 years ago

Which equation represents the circle described?

bazaltina [42]

We have the equation:

$x^2+y^2-8x-6y+24=0$

By arranging this equation in terms of x and y, we have:

$x^2-8x+y^2-6y=-24 \\ \\$

By using the method of completing the square, we have:

$x^2-8x+\mathbf{\left(\frac{8}{2}\right)^2}+y^2-6y+\mathbf{\left(\frac{6}{2}\right)^2}=-24+\mathbf{\left(\frac{8}{2}\right)^2}+\mathbf{\left(\frac{6}{2}\right)^2} \\ \\ x^2-8x+\mathbf{16}+y^2-6y+\mathbf{9}=-24+\mathbf{16}+\mathbf{9} \\ \\ \boxed{(x-4)^2+(x-3)^2=1}$

The center of this circle is:

$(h,k)=(4,3)$

So the equation that fulfills the statement is:

$(x-4)^2+(y-3)^2=2^2$

Finally, the right answer is c)

6 0

3 years ago

Read 2 more answers

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

Yuki888 [10]

$d=v \cdot t$
d - distance
v - speed
t - time

Car A:
$v_1 \\
t_1=2 \\
d_1=v \cdot 2=2 v$

Car B:
15 mph faster than car A
$v_2=v_1+15 \\ t_2=1.5 \\ d_2= (v_1+15) \cdot 1.5=1.5v_1 + 22.5$

Both cars traveled equal distances:
$d_1=d_2 \\
2v_1 = 1.5v_1+22.5 \\
2v_1-1.5v_1=22.5 \\
0.5v_1=22.5 \\
v_1=45 \\ v_2=45 + 15 =60$

Car B traveled at the speed of 60 mph.

6 0

3 years ago

Find the value of 8!<br> O A. 56<br> O B. 16,777,216<br> O c. 40,320<br> O D. 64

Ksivusya [100]

8! is 40,320

Step-by-step explanation:

Step 1: Find 8! (8 factorial).

Factorial of 8 is the product of 8 and all the integers below 8.

⇒ 8! = 8×7×6×5×4×3×2×1

= 40,320

8 0

4 years ago

A 72.5-foot rope from the top of a circus tent pole is anchored to the ground 44.4 feet from the bottom of the pole. What angle

miv72 [106K]

Let angle = x

sinx = 43.2/72.5

=> x = 36.57 degrees

4 0

3 years ago