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Galina-37 [17]
3 years ago
15

Solve the inequality and enter your solution as an inequality comparing the variable to the solution

Mathematics
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

x < 7

Step-by-step explanation:

We are given an equation of inequality and we have to solve the equation as an inequality.

The given equation is - 19 > x - 26

⇒ - 19 + 26 > x

⇒ 7 > x

⇒ x < 7 {Since, if a > b then we can write b < a, as they are equivalent}

Hence,the solution of the equation of the inequality is x < 7. (Answer)

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LenKa [72]
If you are looking for the equation, I’m pretty sure it would be x^2 + 5 + 6. 2 x 3 is 6 and 2 + 3 is 5 so if you factored it out it would be (x + 2) (x + 3). This would mean that your zeroes would be -2 and -3.
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125cm to 87.5cm<br> URGENT<br> I WILL GIVE BRAINLIEST TO CORRECT ANSWER
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7 0
3 years ago
Solve the initial value problem
tigry1 [53]

9(t+1)\dfrac{\mathrm dy}{\mathrm dt}-7y=14t\implies\dfrac{\mathrm dy}{\mathrm dt}-\dfrac7{9(t+1)}y=\dfrac{14t}{9(t+1)}

Look for an integrating factor \mu(t):

\ln\mu=\displaystyle-\frac79\int\frac{\mathrm dt}{t+1}=-\frac79\ln(t+1)\implies\mu=(t+1)^{-7/9}

Multiply both sides by \mu:

(t+1)^{-7/9}\dfrac{\mathrm dy}{\mathrm dt}-\dfrac79(t+1)^{-16/9}y=\dfrac{14}9t(t+1)^{-16/9}

Condense the left side as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[(t+1)^{-7/9}y\right]=\dfrac{14}9t(t+1)^{-16/9}

Integrate both sides:

(t+1)^{-7/9}y=\displaystyle\frac{14}9\int t(t+1)^{-16/9}\,\mathrm dt

For the integral on the right, substitute

u=t+1\implies t=u-1\implies\mathrm dt=\mathrm du

\displaystyle\int t(t+1)^{-16/9}\,\mathrm dt=\int(u-1)u^{-16/9}\,\mathrm du

\displaystyle=\int\left(u^{-7/9}-u^{-16/9}\right)\,\mathrm du=\frac92u^{2/9}+\frac97u^{-7/9}+C

\implies(t+1)^{-7/9}y=\dfrac{14}9\left(\dfrac92(t+1)^{2/9}+\dfrac97(t+1)^{-7/9}+C\right)

\implies(t+1)^{-7/9}y=7(t+1)^{2/9}+2(t+1)^{-7/9}+C

\implies y=7(t+1)+2+C(t+1)^{7/9}=7t+9+C(t+1)^{7/9}

Given that y(0)=12, we get

12=9+C\implies C=3

\implies\boxed{y(t)=7t+9+3(t+1)^{7/9}}

6 0
3 years ago
What is the mean number of bedrooms per house.<br> please answer as soon as possible
pantera1 [17]

Answer:   2.7

============================================

Explanation:

To find the mean, we add up the numbers and divide by the number of items in the set.

For example, the mean of {1,2,6} is 3 because (1+2+6)/3 = 9/3 = 3.

Unfortunately, we don't know how many rooms are in each terraced house. But we do know that the rooms in each terraced house adds to some variable S. Dividing it over 40 gets us the mean of 2.2 rooms per terraced house.

S/40 = 2.2

S = 40*2.2

S = 88

When considering the terraced houses only, there are 88 rooms in total.

Through similar steps, there are 50*2.9 = 145 rooms in the semi-detached houses

And there are 10*3.7 = 37 rooms in the detached houses.

Overall we have 88+145+37 = 270 rooms among the 100 houses total.

The mean number of rooms when considering all three types of houses is 270/100 = 2.7 rooms per house.

---------------------

Another approach:

2.2 is the mean number of rooms for the terraced houses

this represents 40/100 of the entire list

So we'll have (40/100)*2.2 as part of the calculation.

We'll also have (50/100)*2.9 and (10/100)*3.7

The final calculation can be done as this:

(40/100)*2.2 + (50/100)*2.9 + (10/100)*3.7 = 2.7

For more information, check out the concept of a weighted mean.

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3 years ago
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C I believe that it is C also I have bad period cramps send chocolate
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3 years ago
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