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Galina-37 [17]
3 years ago
15

Solve the inequality and enter your solution as an inequality comparing the variable to the solution

Mathematics
1 answer:
weqwewe [10]3 years ago
8 0

Answer:

x < 7

Step-by-step explanation:

We are given an equation of inequality and we have to solve the equation as an inequality.

The given equation is - 19 > x - 26

⇒ - 19 + 26 > x

⇒ 7 > x

⇒ x < 7 {Since, if a > b then we can write b < a, as they are equivalent}

Hence,the solution of the equation of the inequality is x < 7. (Answer)

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The circumference of a circle is 6.28. What is the area of the circle?
masya89 [10]
The area in this case would be 3.14 :)
3 0
3 years ago
A tank contains 60 lb of salt dissolved in 400 gallons of water. A brine solution is pumped into the tank at a rate of 4 gal/min
Natali5045456 [20]

The complete question is;

A tank contains 60 lb of salt dissolved in 400 gallons of water. A brine solution is pumped into the tank at a rate of 4 gal/min; it mixes with the solution there, and then the mixture is pumped out at a rate of 4 gal/min. Determine the amount of salt in the tank at any time

t, if the concentration in the inflow is variable and given by

c(t) = 2 + sin(t/4) lb/gal.

Answer:

dA/dt = (8 + 4sin(t/4)) - (A_t/100)

Step-by-step explanation:

Rate is given as;

dA/dt = R_in - R_out

R_in = (concentration of salt inflow) x (input rate of brine)

So, R_in = (2 + sin(t/4)) x 4 = (8 + 4sin(t/4))

The solution is being pumped out at the same rate, thus it is accumulating at the same rate.

After t minutes, there will be 400 + (0 x t) gallons left = 400 gallons left

Thus,

R_out =(concentration of salt outflow) x (output rate of brine)

R_out = (A_t/400) x 4 = A_t/100

Thus,

A_t = (100/t)(8t - 16cos(t/4) - 60)

Since we want to find the amount of salt, A(t), let's integrate;

Thus, A = 8t - 16cos(t/4) - (A_t/100)t

A = 60 from the question. Thus,

60 = 8t - 16cos(t/4) - (A_t/100)t

Let's try to make A_t the subject;

(A_t/100)t = 8t - 16cos(t/4) - 60

A_t = (100/t)(8t - 16cos(t/4) - 60)

3 0
3 years ago
ach light bulb at Hotel California is either incandescent or fluorescent. At a certain moment, forty percent of the incandescent
Trava [24]

Answer:

10%

Step-by-step explanation:

The computation of the percentage of bulbs that switched on incandescent is as follows;

Let us assume the incandescent be I

And, the fluorescent be F

Now the equation is

0.4I + 0.9F = 0.8 (I+F)

0.41I + 0.9F = 0.8I + 0.8F

So here

0.4I = 0.1F

Now the percentage would be for incandescent in the case of switched on is

= 0.4I ÷  0.8(I+F) × 100

= 0.1F ÷ 1F

= 10%

6 0
3 years ago
A 10-metre long pipe is cut into 2 pieces. One piece is 5 times the length of the other piece. Find the length of each piece, en
elena55 [62]

9514 1404 393

Answer:

  1.67 m, 8.33 m

Step-by-step explanation:

If the ratio of lengths is 1 : 5, then the ratio of the shortest length to the total is ...

  1 : (1+5) = 1 : 6

The shortest length is (10 m)×(1/6) = 1.67 m. The longer length is 10 -1.67 = 8.33 m.

The lengths of the pieces are 8.33 m and 1.67 m.

6 0
3 years ago
Find the matrix that represents a rotation clockwise around origin followed by reflection about x
Westkost [7]
I would have to see the graph

5 0
3 years ago
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