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3 years ago

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A 10-metre long pipe is cut into 2 pieces. One piece is 5 times the length of the other piece. Find the length of each piece, en

tering your answers in metres and rounding your answers to two decimal places.

1 answer:

elena55 [62]3 years ago

6 0

9514 1404 393

Answer:

1.67 m, 8.33 m

Step-by-step explanation:

If the ratio of lengths is 1 : 5, then the ratio of the shortest length to the total is ...

1 : (1+5) = 1 : 6

The shortest length is (10 m)×(1/6) = 1.67 m. The longer length is 10 -1.67 = 8.33 m.

The lengths of the pieces are 8.33 m and 1.67 m.

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50 divided by 70 pluse 10

jok3333 [9.3K]

$50:70+10=\dfrac{50}{70}+10=\dfrac{5}{7}+10=\boxed{10\frac{5}{7}}$

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3 years ago

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Kevin Horn is the national sales manager for National Textbooks Inc. He has a sales staff of 40 who visit college professors all

Oduvanchick [21]

Answer:

Following are the solution to the given points:

Step-by-step explanation:

Given values:

$38, 40, 41, 45, 48, 48, 50, 50, 51, 51, 52, 52, 53, \\\\$ $54, 55, 55, 55, 56, 56, 57, 59, 59, 59, 62, 62, 62, \\ 63, 64, 65,66, 66, 67, 67, 69, 69, 71, 77, 78, 79, 79$

Total staff=40

In point a:

To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.

The midterms =55 and 59 so,

Median = $\frac{55+59}{2} = \frac{114}{2}=57$

In point b:

First-quarter $Q_1 = \frac{1}{4} \text{number of 8th call}$

$=\frac{1}{4} \times 30 th \\\\= 7.5 th$

The first quarterlies are $7.5th \ \ that \ is = (7+0.5)th\ \ term$

therefore the multiply of 0.5 by calculating the difference of the 7th and 8th term are:

$=0.5 \times 0= 0 \\\\\to Q_1 = 50+0=50 \\\\\to Q_3=\frac{3}{4} \text{number of 8th call} \\\\=\frac{3}{4} \times 30 th \\\\=22.5 \ th = (22+0.5)th \ \ term$

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

$= 0.5 \times 1=0.5 \\\\\to Q_3= 63+0.5=63.5$

In point c:

First decile $D_1 = \frac{1}{18} \text{number of 8th call}$

$= \frac{1}{10} \times 30 th \\\\= 3rd \ \ term\\\\\to D_1= 41 \\\\\to D_9= \frac{9}{10} \times 8\ th\ call\\\\=\frac{9}{10} \times 30 th \\\\=27th \ \ term\\\\\to D9 = 67$

In point d:

quartiles are:

$Q_1= 51.25 \\\\Q_3=66$

The right answers for the decile are:

$D_1=45.3 \\\\ D_9=76.4$

As for $D) P_{33} = 53.53$ will be available.

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2 years ago

Starbucks sells their coffee for $3.36 for 24 ounces

Llana [10]

Answer:

Starbucks by 1 cent difference.

Step-by-step explanation:

Divide: 3.36 divided by 24 to find Starbucks. You get 14 cents per ounce

Divide: 2.40 divided by 16 to find Circle K. You get 15 cents per ounce

Compare: Starbucks is cheaper by 1 cent.

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Aleksandr [31]

I think the answer a

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3 years ago

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Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)

lisov135 [29]

Answer:

(a) The system of the equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ has no solution.

(b) The system of the equations $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ has many solutions $y=\frac{2x}{3}-\frac{5}{3}$

Step-by-step explanation:

(a) To find the solutions of the following system of equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ you must:

Multiply $2x-3y=3$ by 2:

$\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}$

Subtract the equations

$4x-6y=3\\-\\4x-6y=6\\------\\0=-3$

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ you must:

Isolate x for $4x-6y=10$

$x=\frac{5+3y}{2}$

Substitute $x=\frac{5+3y}{2}$ into the second equation

$16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40$

The system has many solutions.

Isolate y for $4x-6y=10$

$y=\frac{2x}{3}-\frac{5}{3}$

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3 years ago