9514 1404 393
Answer:
(c) CPCTC
Step-by-step explanation:
The proof might go something like this:
- EH ≅ KH, FH ≅ JH . . . . . given
- ∠EHF ≅ ∠KHJ . . . . . vertical angles are congruent
- ∆EHF ≅ ∆KHJ . . . . . SAS congruence theorem
- EF ≅ KJ . . . . . CPCTC
Note that JK is an alternate name for segment KJ. We used KJ in the proof because vertices K and J correspond directly to vertices E and F in the congruent triangles.
Cross multiply
2x(3x-4) = 3(x+2)
5x - 8x = 3x + 6
-3x= 3x+6
x = 6
I think
Answer:
x1 = 8+√10, x2 = 8 -√10
Step-by-step explanation:
x² - 16x + 54 = 0
Answer:
9.23 x 10^9
Step-by-step explanation:
V=lwh
198 = 3(x-1)(x-4)
(x-1)(x-4)=x^2-5x+4
3(x^2-5x+4)
= 3x^2-15x+12
3x^2-15x+12=198
Subtract 198 from both sides
= 3x^2-15x-186
use Quadratic formula <-- google if you forgot it
=10.761355820929152 and a different number which is negative, so reject it
Round it to 10.76
x=10.76