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3 years ago

Help me with answering this question

Mathematics

1 answer:

Ksju [112]3 years ago

6 0

Answer:

x-intercept is (-4,0) and the y-intercept is (0,-2

Step-by-step explanation:

There are 2 ways to find the y-intercept. One way is to put the equation in slope-intercept form. However, there is a more efficient way as well.

Another way to do it is to plug 0 in for x and y. The x-intercept will have the coordinate of (x,0). So to find the x-intercept you can plug in 0 for y and solve for x. To find the y-intercept do the opposite and plug 0 in for x.

So, first, plug 0 in for y

x+2(0)=-4
x+0=-4
x=-4

Then plug in 0 for x

0+2y=-4
2y=-4
y=-2

Therefore, the x-intercept is (-4,0) and the y-intercept is (0,-2).

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The equation of the regression line for the following data is:

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Step-by-step explanation:

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Step-by-step explanation:

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What types of solutions does 6x^2 - 20x + 1 have?

elena55 [62]

Answer:

2 real solutions

Step-by-step explanation:

We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:

b² - 4ac

If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.

Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:

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3 years ago

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babymother [125]

Answer:

The answer to your question is:th first option is correct.

Step-by-step explanation:

Here we have and hyperbola with center (0, 1), and the hyperbola is horizontal because x² is positive.

Equation

y - k = ± $\frac{b}{a} (x - h)$

Process

Find a, b

a² = 9

a = 3

b² = 5

b = √5

h = 0 and k = 1

Substitution

y - 1 = ± $\frac{√5}{3} (x - 0)$

Equation 1

y = $\frac{\sqrt{5} }{3} x + 1$

Equation 2

y = - $\frac{\sqrt{5} }{3} x + 1$

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