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Virty [35]
3 years ago
8

I NEED HELP ASAP WILL GIVE BRAINLIEST

Mathematics
2 answers:
nadezda [96]3 years ago
8 0
It is a because it is right
aniked [119]3 years ago
5 0

Step-by-step explanation:

length of missing side = sqrt(5^2 + 12^2) = sqrt(169) = 13

distance = sqrt(50^2 +25^2) =sqrt(3125)= 55.90metres

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freds dog crate is 42 inches long, 24 inches wide, and has a height of 30 inches. what is the volume of the crate?
laila [671]

Answer:

20 icnhes

Step-by-step explanation:

not rlly

4 0
4 years ago
Sophia exchanged 1000 U.S. dollars for the South African currency which is called the rand. The exchange rate was 8.05 rand to 1
saw5 [17]

Answer:

Sophia gets 7,150

Step-by-step explanation:

6 0
3 years ago
Please help me with this question:<br> 6px3=3x6p= ____p
Ivanshal [37]

Answer:

   12

Step-by-step explanation:

It looks like you're given the equations ...

  6px^3 = 3x^6p

Dividing both sides by 3px^3, we get ...

 2 = x^3

Substituting that into the left side of the equation, we have ...

  6px^3 = 12p

It appears this is the expression you want on the right.

  6px^3 = 3x^6p = 12p

8 0
4 years ago
Read 2 more answers
An experiment consists of first rolling a die and then tossing a coin: A. How many elements are there in the sample space? B. Le
stepladder [879]

Answer:

A) There are 12 elements in the sample space.

B) The required probability is 1/4 or 0.25.

C) Yes, the events are mutually exclusive.

Step-by-step explanation:

Consider the provided information.

Part(A)

An experiment consists of first rolling a die and then tossing a coin.

Thus the sample space is:

(1,H), (2,H) (3,H) (4,H) (5,H), (6,H)

(1,T), (2,T) (3,T) (4,T) (5,T), (6,T)

Hence, there are 12 elements in the sample space.

Part(B) Let A be the event that either a 2, 3 or 4 is rolled first, followed by landing a head on the coin toss.

Now consider the above sample space. There are 3 possible case in which 2, 3 or 4 is rolled first, followed by landing a head on the coin toss.

i.e (2,H) (3,H) (4,H)

The required probability is: P(A)=\frac{3}{12}=\frac{1}{4}=0.25

Hence, the required probability is 1/4 or 0.25.

Part(C)

Mutually exclusive, means that they cannot occur at the same time.

From part (B) Event A = (2,H) (3,H) (4,H)

Let B be the event that a number less than 2 is rolled, followed by landing a head on the coin toss.

Thus, the Event B = (1,H).

Therefore, Event A and B can't be occur at the same time as P(A and B)=0.

Hence, yes, the events are mutually exclusive.

7 0
3 years ago
I WILL MARK AS BRAINLIEST! Find the surface area and Volume of the following figures
abruzzese [7]

Step-by-step explanation:

a) is really easy, right ?

the surface area consists of 6 rectangles (as you know, every die has 6 sides). they are 3 pairs of equally sized rectangles.

there are 2 rectangles 7×1, 2 rectangles 7×2, and 2 rectangles 2×1

SA = 2×7×1 + 2×7×2 + 2×2×1 = 14 + 28 + 4 = 46 in²

the volume is just length×width×height

V = 7×2×1 = 14 in³

b)

a little bit more difficult, but with a little trick just as easy.

the surface area consists of the 2 circle areas and the mantle "coating".

the area of a circle is pi×r².

we have to be careful as the given 10 ft is the diameter of these circles. the radius is half of it : 5 ft.

the area of the "mantle" we can calculate by imagining we simply slice it open with one straight line from top to bottom. and then we cut it off the two circles and put it flat on the table.

now we see it is just a rectangle. one side is 12ft. the other is the circumference of the previously attached circles.

circumference of a circle is 2×pi×r

so the surface area is 2×circle + (circumference circle)×12

SA = 2×pi×5² + (2×pi×5)×12 = 50pi + 120pi = 170pi =

≈ 534.07 ft²

the volume is one base area (circle) times height

V = pi×5²×12 = 300pi ≈ 942.48 ft³

7 0
3 years ago
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