Answer:
speed = 796142.197 km/hr
Step-by-step explanation:
solution
we consider here orbit around galactic center is circular so
circumference formula will be here
circumference C = 2πr ........1
here we know r = 27000
so
circumference C = 2 π × 27000
C = 169560 light year
so
we travel 169560 light year in 230000000 years
so distance will be
distance = 
distance = 0.00073721 light year/year
and we know 1 year = 8760 hours
so 1 light year = 9.46027 ×
km
so
sped of moving is
speed = 0.00073721 × 9.46027 ×
km/hr
speed = 796142.197 km/hr
Answer:

Step-by-step explanation:

Hope this helps!
Answer:
The standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 175760000
Step-by-step explanation:
If there are no restrictions, all numbers and letters are available to be used then. And with no restrictions, every number or letter can appear more than once.
There are 7 spaces available; 3 spaces for letters, 4 spaces for numbers
The different combination of letters and numbers then becomes,
26 × 26 × 26 × 10 × 10 × 10 × 10
This is because, all 26 letters (A to Z) can occupy the first space, the second space and the third space. And all 10 digits (0 to 9) can occupy the fourth space, the fifth space, the sixth space and the seventh space.
So, the standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 26 × 26 × 26 × 10 × 10 × 10 × 10 = 175760000 different standard issue license plates.