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2 years ago

(−m 2 +6)+(−4m 2 +7m+2)

Mathematics

1 answer:

dmitriy555 [2]2 years ago

7 0

Following are calculation to the given eqution:

Given:

$\bold{(-m^2+6)+(-4m^2+7m+2)}$

To find:

Solve the equation.

Solution:

$\to \bold{(-m^2+6)+(-4m^2+7m+2)}\\\\\to \bold{-m^2+6-4m^2+7m+2}\\\\\to \bold{-5m^2+7m+8}\\\\\to \bold{-1(5m^2-7m-8)}\\\\$

Therefore, the final solution is " $-1(5 m^2-7m-8)$ ".

Learn more:

brainly.com/question/12685776

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Second one is 87

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A: What are the solutions to the quadratic equation x2+9=0? B: What is the factored form of the quadratic expression x2+9? Selec

Paraphin [41]

Answer:

A. The solutions are $x=3i,\:x=-3i$ .

B. The factored form of the quadratic expression $x^2+9=(x-3i)(x+3i)$

Step-by-step explanation:

A. To find the solutions to the quadratic equation $x^2+9=0$ you must:

$\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}$

$x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i$

The solutions are:

$x=3i,\:x=-3i$

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor $x^2+9$ :

First, multiply the constant in the polynomial by $i^2$ where $i^2$ is equal to -1.

$x^2+9i^2$

Since both terms are perfect squares, factor using the difference of squares formula

$a^2-i^2=(a+i)(a-i)$

$x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)$

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