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Alexeev081 [22]
3 years ago
15

Which would be a correct first step to solve the following system of linear equations using the elimination method? 2x+3y=6

Mathematics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

Subtract

Step-by-step explanation:

Subtract to eliminate the y value so all that is left to slove is the x value. Once you have the x value, you can plug it in to find the y value.

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30 + 6p = 7 (p+ 6 ) -5<br> Please answer
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Answer: p=-7

Step-by-step explanation:

To solve for p, you want to isolate the variable, get p alone. You would use different algebraic properties to do so.

30+6p=7p+42-5

30+6p=7p+37

-7=p

p=-7

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Vector u has a magnitude of 7 units and a direction angle of 330°. Vector v has magnitude of 8 units and a direction angle of 30
Dafna11 [192]
Keeping in mind that x = rcos(θ) and y = rsin(θ).

we know the magnitude "r" of U and V, as well as their angle θ, so let's get them in standard position form.

\bf u=&#10;\begin{cases}&#10;x=7cos(330^o)\\&#10;\qquad 7\cdot \frac{\sqrt{3}}{2}\\&#10;\qquad \frac{7\sqrt{3}}{2}\\&#10;y=7sin(330^o)\\&#10;\qquad 7\cdot -\frac{1}{2}\\&#10;\qquad -\frac{7}{2}&#10;\end{cases}\qquad \qquad v=&#10;\begin{cases}&#10;x=8cos(30^o)\\&#10;\qquad 8\cdot \frac{\sqrt{3}}{2}\\&#10;\qquad \frac{8\sqrt{3}}{2}\\&#10;y=8sin(30^o)\\&#10;\qquad 8\cdot \frac{1}{2}\\&#10;\qquad 4&#10;\end{cases}

\bf u+v\implies \left( \frac{7\sqrt{3}}{2},-\frac{7}{2} \right)+\left( \frac{8\sqrt{3}}{2},4 \right)\implies \left( \frac{7\sqrt{3}}{2}+\frac{8\sqrt{3}}{2}~~,~~ -\frac{7}{2}+4\right)&#10;\\\\\\&#10;\left(\stackrel{a}{\frac{15\sqrt{3}}{2}}~~,~~  \stackrel{b}{\frac{1}{2}}\right)\\\\&#10;-------------------------------

\bf tan(\theta )=\cfrac{b}{a}\implies tan(\theta )=\cfrac{\frac{1}{2}}{\frac{15\sqrt{3}}{2}}\implies tan(\theta )=\cfrac{1}{15\sqrt{3}}&#10;\\\\\\&#10;\measuredangle \theta =tan^{-1}\left( \cfrac{1}{15\sqrt{3}} \right)\implies \measuredangle \theta \approx 2.20422750397203^o
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Finding the function of y=-2/3x +2​
nordsb [41]

Answer:2 x + 3 y = 6

Step-by-step explanation:

in standard form

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