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horrorfan [7]
3 years ago
13

F(x)=15x^2+360 , find x ?

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0
Ok........
 X would be
X = 1 plus or minus \sqrt[i]{21599}
                                              -------------------
                                                       30

H0P3 It H3LPS :)



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Do you guys do proofs for math.
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Please SHOW WORK, will mark brainlist if correct
riadik2000 [5.3K]

Answer:

\huge\boxed{\sf \frac{x+3}{x-3}}

Step-by-step explanation:

\displaystyle = \frac{x+7}{x^2+4x-21} \div \frac{x+5}{x^2+8x+15} \\\\Apply \ mid-term \ break\\\\= \frac{x+7}{x^2 +7x-3x-21} \div \frac{x+5}{x^2 +3x+5x+15} \\\\= \frac{x+7}{x(x+7)-3(x+7)} \div \frac{x+5}{x(x+3)+5(x+3)} \\\\Taking \ (x+3) \ and \ (x+7) \ common\\\\= \frac{x+7}{(x-3)(x+7)} \div \frac{x+5}{(x+3)(x+5)} \\\\= \frac{1}{x-3} \div \frac{1}{x+3} \\\\= \frac{1}{x-3} * (x+3)\\\\= \frac{x+3}{x-3} \\\\\rule[225]{225}{2}

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Step-by-step explanation:

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I hope this helped you, have a great day! :)

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Read 2 more answers
For the following exercises, evaluate the function at the indicated values:
STALIN [3.7K]

Answer:

The evaluated function for the indicated values is given below.

The value of f(-3) is 20 .

The value of f(2) is 10 .

The value of f(-a) is $2|-3 a-1|$.

The value of -f(a) is $-2|3 a-1|$.

The value of f(a+h) is $2|3 a+3 h-1|$.

Step-by-step explanation:

A function $f(x)=2|3 x-1|$ is given.

It is required to evaluate the function at $f(-3) ; f(2) ; f(-a) ;-f(a) ; f(a+h)$.

To evaluate the function, substitute the indicated values in the given function to determine the output values and simplify the expression.

Step 1 of 5

The given function is $f(x)=2|3 x-1|$.

To evaluate the function at f(-3), substitute -3 in the given function f(x)=2|3 x-1|$\\ $f(-3)=2|3(-3)-1|$\\ $f(-3)=2|-9-1|$\\ $f(-3)=2|-10|$\\ $f(-3)=2(10)$\\ $f(-3)=20$

Step 2 of 5

To evaluate the function at $f(2)$, substitute 2 in the given function.

f(x)=2|3 x-1|$\\ $f(2)=2|3(2)-1|$\\ $f(2)=2|6-1|$\\ $f(2)=2(5)$\\ $f(2)=10$

Step 3 of 5

To evaluate the function at f(-a), substitute -a in the given function.

$$\begin{aligned}&f(x)=2|3 x-1| \\&f(-a)=2|3(-a)-1| \\&f(-a)=2|-3 a-1|\end{aligned}$$

Step 4 of 5

To evaluate the function at -f(a), substitute a in the given function.

f(x)=2|3 x-1|$\\ $-f(a)=-2|3(a)-1|$\\ $-f(a)=-2|3 a-1|$

Step 5 of 5

To evaluate the function at f(a+h), substitute a+h in the given function. $f(x)=2|3 x-1|$

$$\begin{aligned}&f(a+h)=2|3(a+h)-1| \\&f(a+h)=2|3 a+3 h-1|\end{aligned}$$

7 0
2 years ago
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