<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.
Answer:
Step-by-step explanation:
let number of passion fruits=x
number of dragon fruits=x+10% of x
=x+0.1 x=(1+0.1)x=1.1 x
total number of fruits=x+1.1 x=(1+1.1)x=2.1 x
1.1x+60% of 1.1x+x+9% of x=2.1x+75
1.1 x+0.6 of 1.1 x+x+0.09 of x=2.1x+75
1.1x+0.66 x+x+0.09 of x =2.1x+75
2.1 x+0.75x-2.1 x=75
0.75 x=75
That will be =3x10 with the baby 3 on top of the 10 and that also equals 3000
