Answer: population; independently
Step-by-step explanation:
A random sample selected from an infinite population is a sample selected such that each element selected comes from the same *population* and each element is selected *independently*.
70/6 × 18/4
70 * 18/6*4. cross out 18 and 6.
= 70*3/4
= 35 * 2 * 3/ 2*2
= 35*3/2
= 105/2
= 52.5
OR
52 1/2.
<h2>
Answer with explanation:</h2>
It is given that:
f: R → R is a continuous function such that:
∀ x,y ∈ R
Now, let us assume f(1)=k
Also,
( Since,
f(0)=f(0+0)
i.e.
f(0)=f(0)+f(0)
By using property (1)
Also,
f(0)=2f(0)
i.e.
2f(0)-f(0)=0
i.e.
f(0)=0 )
Also,
i.e.
f(2)=f(1)+f(1) ( By using property (1) )
i.e.
f(2)=2f(1)
i.e.
f(2)=2k
f(m)=f(1+1+1+...+1)
i.e.
f(m)=f(1)+f(1)+f(1)+.......+f(1) (m times)
i.e.
f(m)=mf(1)
i.e.
f(m)=mk
Now,

Also,
i.e. 
Then,

(
Now, as we know that:
Q is dense in R.
so Э x∈ Q' such that Э a seq
belonging to Q such that:
)
Now, we know that: Q'=R
This means that:
Э α ∈ R
such that Э sequence
such that:

and


( since
belongs to Q )
Let f is continuous at x=α
This means that:

This means that:

This means that:
f(x)=kx for every x∈ R
Answer:0.60
Step-by-step explanation:
Multiply the denominator (5) and the numerator (3) by 20. Both sides multiplied equals 60 as the numerator and 100 as the denominator. After the conversions to a decimal, your answer should be 0.60 since 60/100=0.60.
Answer:
Step-by-step explanation:
a. The hypothesis test is one tailed_____ test.
(Because we check whether sample weight is greater than hence one tailed or right tailed)
The test statistic follows a __t___ distribution.(Because only sample std deviation s is known)
The value of the test statistic is___Mean difference/Std error =
__
b. df = 66
Reject H0 if t ≥ 1.668
c. The p-value is_____0.059444
d. Using the critical value approach, the null hypothesis is _accepted____, because __t <1.668___ Using the p-value approach, the null hypothesis is__accepted___, because__p value <0.05 our significance level.___ Therefore, you __may___ conclude that the mean weight of the airline's passengers' carry-on items has increased after the implementation of the checked-bag fee.