16°C
<h2>Explanation:</h2>The equation relating temperature with resistance is given as follows;
=
[
(
-
) + 1] --------------(i)
<em>Where;</em>
= Temperature at some reference point
= Resistance at the reference point
T = Temperature at some other point
= Resistance at the other point
= constant called "temperature coefficient of the resistor material"
<em>From the question; </em>
Let's take the reference point temperature () as 4.00°C;
Therefore;
= Resistance at the reference point = 217.4Ω
= Resistance at the other point = 216.0Ω
= Temperature coefficient of the resistor material (carbon) = -0.0005/°C
<em>Now substitute these values into equation (i) as follows;</em>
216.0 = 217.4 [(-0.0005)( - 4) + 1]
216.0 = 217.4 [-0.0005 + 0.002 + 1]
216.0 = 217.4 [-0.0005 + 1.002]
<em>Divide through by 217.4 as follows;</em>
0.994 = 1.002 - 0.0005T
<em>Solve for T;</em>
0.0005T = 1.002 - 0.994
0.0005T = 0.008
T = 0.008 / 0.0005
T = 16°C
Therefore, the temperature on a spring day at that resistance is 16°C
