All categories

3 years ago

PLS HELP ME OUT!!

Physics

2 answers:

MaRussiya [10]3 years ago

4 0

In order to solve this problem, we must first find out the value of each line on the number line. However, we can make this problem more simple by ignoring every interval except for the ones between 0 and 6. There are three total intervals in between 0 and 6 (including 6 and excluding 0). Therefore, we can do 6/2, and get an interval value of 2. This means that each line adds a value of 2. Since the car is only one line past zero, we only have to add one value of 2. Since 0 + 2 = 2, our final answer is C. 2.

Hope this helps!

Tamiku [17]3 years ago

4 0

c. 2

Explanation:

Before solving the problem, we should understand what is the length that corresponds to one notch in the graph.

We see that there are 3 notches between 0 and 6, and that the length of the notches is constant: so, each notch corresponds to the same length. Since we have 3 notches, the length of each notch is

$\frac{6}{3}=2$

Since the car is located at the first notch, it means that its position is:

$x=1 \cdot 2 = 2$

You might be interested in

3. Force = _____ x _____?

harkovskaia [24]

Answer:

Explanation:

Force = mass * acceleration.

8 0

3 years ago

When the mirror is rotated, the normal will turn as well, but will the incident Ray and reflected ray turn?

Inessa [10]

When a mirror is rotated . . .

-- The incident ray doesn't turn. It's just the line from the source to the mirror.
It would be there, in the same place, even if there was no mirror.

-- The normal turns. It's the line perpendicular to the mirror, so it must turn
with the mirror.

-- Since the normal tuns and the incident ray doesn't, the angle between them
must change. And since the angle of the reflected ray is equal to the angle of
the incident ray, the reflected ray must also turn.

6 0

3 years ago

What are two important uses of petroleum

Delvig [45]

Some are fuel,chemicals,plastics,asphalt,and road oil.

5 0

3 years ago

Read 2 more answers

A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline

balandron [24]

Answer:

2.78m/s²

Explanation:

Complete question:

A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?

According to Newton's second law of motion:

$\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\$

Where:

$\mu$ is the coefficient of friction

g is the acceleration due to gravity

Fm is the moving force acting on the body

Ff is the frictional force

m is the mass of the box

a is the acceleration'

Given

$\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2$

Required

acceleration of the box

Substitute the given parameters into the resulting expression above:

Recall that:

$gsin\theta - \mu g cos\theta = a_x\\$

9.8sin30 - 0.25(9.8)cos30 = ax

9.8(0.5) - 0.25(9.8)(0.866) = ax

4.9 - 2.1217 = ax

ax = 2.78m/s²

Hence the acceleration of the box as it slides down the incline is 2.78m/s²

5 0

3 years ago

A car with a mass of 1. 2 × 103 kilograms starts from rest and attains a speed of 20 meters/second in 5 seconds. What net force

GaryK [48]

Answer:

The formula for force according to Newton's second law of motion is F=ma or force for an object to move is equal to mass times acceleration.

Acceleration or average acceleration defined as change in velocity per time.

F=ma

F=1.2x10³kg*(20m/s)(1/5s)=4.8x10³ Newtons

Explanation:

fthat's not the answer then i'm sorry

3 0

3 years ago