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3 years ago

PLS HELP ME OUT!!

Physics

2 answers:

MaRussiya [10]3 years ago

4 0

In order to solve this problem, we must first find out the value of each line on the number line. However, we can make this problem more simple by ignoring every interval except for the ones between 0 and 6. There are three total intervals in between 0 and 6 (including 6 and excluding 0). Therefore, we can do 6/2, and get an interval value of 2. This means that each line adds a value of 2. Since the car is only one line past zero, we only have to add one value of 2. Since 0 + 2 = 2, our final answer is C. 2.

Hope this helps!

Tamiku [17]3 years ago

4 0

c. 2

Explanation:

Before solving the problem, we should understand what is the length that corresponds to one notch in the graph.

We see that there are 3 notches between 0 and 6, and that the length of the notches is constant: so, each notch corresponds to the same length. Since we have 3 notches, the length of each notch is

$\frac{6}{3}=2$

Since the car is located at the first notch, it means that its position is:

$x=1 \cdot 2 = 2$

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What type of medium (solids, liquids, or gases) do sound waves travel fastest in?

Pavel [41]

Answer:

Gases

Explanation:

Gases molecules are farther apart than solids and liquids. :)

5 0

3 years ago

Air at 38oC and 97% relative humidity is to be cooled to 14oC and fed into a plant area at a rate of 510 m3/min. Calculate the r

bekas [8.4K]

Answer:

mass flow rate at water condenses is 36.72 kg/min

Explanation:

given data

temperature t1 = 38°C

temperature t2 = 14°C

humidity ∅= 97 % = 0.97

rate v = 510 m³/min

to find out

mass flow rate at water condenses

solution

by gas equation we find here mass flow rate that is

pv = mRT

put here value and p is 0.066626 bar at 38°C and find m

m = 0.06626 × $10^{5}$ × 510 / 287×311

m = 37.85 kg/min

so at water condenses mass flow rate is express as

∅ = M / m

Mass flow rate M = ∅ × m

M = 0.97 × 37.85

mass flow rate = 36.72 kg/min

so mass flow rate at water condenses is 36.72 kg/min

8 0

3 years ago

A heat engine extracts 42. 53 kj from the hot reservior and exhausts 17. 69 kj into the cold reservior. what is the work done?

ludmilkaskok [199]

The answer is 24.84kJ.

We apply the expression for the work done by the heat engine is,

$W=E_{i n}-E_{o u t}$ . Putting all given values in the equation we get the final answer.

What is heat engine?

A heat engine is a machine that uses heat to generate power. It draws heat from a reservoir, uses that heat to produce work, such as move a piston or lift weights, and then releases that heat energy into the sink.
We are given:The heat input is $E_{i n}=42.53 \mathrm{~kJ}$ . The heat output is $E_{o u t}=17.69 \mathrm{~kJ}$ .
The expression for the work done by the heat engine is, $W=E_{i n}-E_{o u t}$
Substituting the given values in the above expression, we will get $W =42.53 \mathrm{~kJ}-17.69 \mathrm{~kJ}$ =24.84kJ.
Thus, the work done by the heat engine is 24.84kJ.