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Liono4ka [1.6K]
3 years ago
13

Which physical properties can be used to identify an unknown material?

Physics
2 answers:
IRISSAK [1]3 years ago
7 0
"Mass" and "solubility" are the two physical properties among the following choices given in the question that <span>can be used to identify an unknown material. The correct options among all the options that are given in the question are option "B" and option "D". I hope that the answer has come to your help.</span>
stellarik [79]3 years ago
5 0

C.) Melting point

D.) Solubility

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An object travels 20 m in 10s What is its speed?
ella [17]

speed=distance/time

distance=20m

time=10s

speed=?

speed=20×10

speed=200m/s

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3 years ago
"how do the fundamental laws of physics make manifest that space has 3 dimensions?"
bazaltina [42]
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When you go right into detail, the fundamental laws governing these proofs are very technical. They have differential equations to show as proof. It is too detailed to discuss here. The important things is that, these fundamental laws are what explains the science in our basic activities and natural phenomena:

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3 years ago
when two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of
Ahat [919]

<h2>When two object P and Q are supplied with the same quantity of heat, the temperature change in P is observed to be twice that of Q. The mass of P is half that of Q. The ratio of the specific heat capacity of P to Q​</h2>

Explanation:

Specific heat capacity

It is defined as amount of heat required to raise the temperature of a substance by one degree celsius .

It is given as :

Heat absorbed = mass of substance x specific heat capacity x rise in temperature

or ,

Q= m x c x t

In above question , it is given :

For Q

mass of Q = m

Temperature changed =T₂/2

Heat supplied = x

Q= mc t

or

X=m x C₁ X T₁

or, X =m x C₁ x T₂/2

or, C₁=X x 2 /m x T₂                                 (equation 1 )

For another quantity : P

mass of P =m/2

Temperature= T₂

Heat supplied is same that is : X

so, X= m/2 x C₂ x T₂                            

or, C₂=2X/m. T₂                                   (equation 2 )

Now taking ratio of C₂ to c₁, We have

C₂/C₁= 2X /m.T₂  /2X  /m.T₂

so, C₂/C₁= 1/1

so, the ratio is 1: 1

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Do you have the equation for half life
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