I think it is the bottom left
Answer:
Vanilla milkshake = 1/3 and Chocolate milkshake = 2/3
Step-by-step explanation:
Given data:
Total ounce of milkshake = 12 ounce
Vanilla milkshake = 4
Chocolate is the rest <em>which can be interpreted as 12 - 4= 8 ounce</em>
Representing as fractions
<em>Vanilla milkshake = </em>4/12 <em>(Reducing to lowest terms that is diving numerator and denominator by common factor in this case 4)</em>
Vanilla milkshake = 1/3
Chocolate milkshake = 8/12 <em>(Reducing to lowest terms that is diving numerator and denominator by common factor in this case 4)</em>
Chocolate milkshake = 2/3
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Answer:
-1<x<1 and 1<x
Step-by-step explanation:
We are asked to determine the interval in which our function shown in the graph has positive values.
In order to do so, we have to see for what values of x on x axis, the graph is above x axis.
As we can see in the graph, when we move from x = -1 towards right, the graph is above x axis. And towards left of x=-1 , the graph is below x axis. Hence answer is
-1<x<1 and 1<x
We have the following function:
C (t) = 6t - 180
Clearing t we have:
6t = c + 180
t = c / 6 + 180/6
Rewriting:
t (c) = (c + 180) / 6
Answer:
The inverse function for this case is given by:
t (c) = (c + 180) / 6
option A
Answer:
The function f(x) has a vertical asymptote at x = 3
Step-by-step explanation:
We can define an asymptote as an infinite aproximation to given value, such that the value is never actually reached.
For example, in the case of the natural logarithm, it is not defined for x = 0.
Then Ln(x) has an asymptote at x = 0 that tends to negative infinity, (but never reaches it, as again, Ln(x) is not defined for x = 0)
So a vertical asymptote will be a vertical tendency at a given x-value.
In the graph is quite easy to see it, it occurs at x = 3 (the graph goes down infinitely, never actually reaching the value x = 3)
Then:
The function f(x) has a vertical asymptote at x = 3
