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Alex_Xolod [135]
2 years ago
13

In a box there are 6 orange balls, 4 green balls and "x" blue balls. If the probability of removing a blue ball is 1/3, what is

the probability of removing two blue bags?
Mathematics
1 answer:
worty [1.4K]2 years ago
4 0

Answer: 2/3 I think

Step-by-step explanation:

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It is not likely because it is less then 50% which 50 is half and 25% is 1/4 chance.
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Solve the equation for x.<br> 42 + 5x = 41
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Answer:

x= -0.2 or -1/5

Step-by-step explanation:

42+5X=41

Subtract 42 from both sides:

42+5X=41

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You are left with:

5x=-1

Now divide 5 by both sides to isolate x:

5x= -1

---    ---

5       5

x=-0.2 or -1/5

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Please help me please I really need help
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Step-by-step explanation:

The answer is attached

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3 years ago
For what values of x is log base 0.8 (x+4)&gt;log base 0.4 (x+4)<br>Thank you!
Radda [10]
We are seeking the solution of the inequality:

\displaystyle{ \log_{0.8}(x+4)\ \textgreater \ \log_{0.4}(x+4).


We recall that a log function f(x)=\log_b(x) is either increasing or decreasing:

i) it is increasing if b>1, 

ii) it is decreasing if 0<b<1.

Consider the functions \displaystyle{ \log_{0.8}(x) and \displaystyle{ \log_{0.4}(x).

The graphs of these functions both meet at x=1 (clearly), and after 1 they are both negative. So from 0 to 1 one of them is larger for all x, and from 1 to infinity the other is larger. (Being strictly decreasing, their graphs can only intersect once.)


We can check for a certain convenient point, for example x=0.8:

\displaystyle{ \log_{0.8}(0.8)=1 and

\displaystyle{ \log_{0.4}(0.8)=\log_{0.4}(0.4\cdot 2)=\log_{0.4}(0.4)+\log_{0.4}(\cdot 2)=1+\log_{0.4}(2).

Now, \displaystyle{ \log_{0.4}(2) is negative since we already explained that for x>1 both functions were negative. This means that 

\displaystyle{ \log_{0.8}(0.8)\ \textgreater \ \log_{0.4}(0.8), and since 0.8\in (0, 1), then this is the interval where \displaystyle{ \log_{0.8}(x)\ \textgreater \ \log_{0.4}(x).


So, now considering the functions \displaystyle{ \log_{0.8}(x+4) and \displaystyle{ \log_{0.4}(x+4), we see that 

x+4 must be in the interval (0,1), so we solve:

0<x+4<1, which yields -4<x<-3 after we subtract by 4.


Answer: (-4, -3). Attached is the graph generated using Desmos.

7 0
3 years ago
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