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Alex_Xolod [135]
2 years ago
13

In a box there are 6 orange balls, 4 green balls and "x" blue balls. If the probability of removing a blue ball is 1/3, what is

the probability of removing two blue bags?
Mathematics
1 answer:
worty [1.4K]2 years ago
4 0

Answer: 2/3 I think

Step-by-step explanation:

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Answer:

y= -3/4x-2

Step-by-step explanation:

- perpendicular: opposite signs and reciprocal

m= -3/4

point-slope form: y-y1=m(x-x1)

y-(-1)= -3/4(x-(-4))

y+1= -3/4(x+4)

y+1= -3/4x -3

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Answer:

Step-by-step explanation:

A box contains four cards: One card is black on both sides, one card is red on both sides and two cards are black on one side and red on the other side. One card is selected at random and you can see only one side.i) If the side you see is black, what is the probability that the other side is black?ii) If the side you see is black, what is the probability that the other side is red?

Given that:

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y = Red on both sides = 1

z = Black on one side, red on one side = 2

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Probability of black

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which of what? no answer choices.

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Find all real solutions:<br> x² - x - 12 = 0
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x^2-x-12= 0
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Use the zero product property to find roots
x-4=0
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x+3=0
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Final answer: x=-3, x=4
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