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2 years ago

13

Find the measure of the arc

1 answer:

Natali [406]2 years ago

4 0

Hmmm I think it’s...

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(2/3)-(1/X+6)=2 solve for x

nata0808 [166]

We have a fraction with the unknown in the denominator, review how to treat unknowns in the denominator as a refresher for this exercise:
<span>(2/3) - (1/x + 6) = 2
</span>(2/3) - (1 + 6x)/x = <span>2
</span>(2/3) - 2 = (1 + 6x)/x
2/3 - 6/3 = (1 + <span>6x)/x
-4/3 = </span>(1 + <span>6x)/x
-4x = 3</span>(1 + <span>6x)
</span><span>-4x = 3 + 18x
</span>22x = -3
x = -3/22

8 0

3 years ago

Write the composite function in the form f(g(x)). [Identify the inner function u = g(x) and the outer function y = f(u).] y = ta

Irina-Kira [14]

Answer:

The inner function is $u = \pi x$ .

The outer function is $f(u) = \tan{u}$ .

$\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}$

Step-by-step explanation:

The inner function is the one we apply the outer function to.

So

$y = \tan{\pi x}$

We apply the outer function tangent to $\pi x$ .

So, the inner function is $u = \pi x$ .

The outer function is $f(u) = \tan{u}$ .

The derivative of a compositve function

$y = f(u)$ in which $u = g(x)$ is given by the following function.

$y^{\prime} = f^{\prime}(u)*g^{\prime}(x)$

So

$f(u) = \tan{u}$

$f^{\prime}(u) = \sec^{2}{u}$

$u = g(x) = \pi x$

$g^{\prime}(x) = \pi$

So

$y^{\prime} = f^{\prime}(u)*g^{\prime}(x)$

$\frac{dy}{dx} = y^{\prime} = \sec^{2}(u)*\pi = \pi\sec^{2}{\pi x}$

7 0

2 years ago

If a string that is 15.5 inches long is cut into equal pieces that are 1.25 inches long, how many pieces of ribbon can be create

tamaranim1 [39]

Number created = 15.5 / 1.25 = 12.4

8 0

2 years ago

A rectangular prism and its dimensions are shown in the diagram.

Sergeu [11.5K]

Answer:

148.2

Step-by-step explanation:

LA= PH

P= 8.2+8.2+3.2+3.2=22.8 in

H= 6.5 in

PH= 22.8(6.5)= 148.2 in

8 0

2 years ago

Which table shows a constant rate of change of –3?

Zinaida [17]

I belive the answer is the 3rd one

5 0

3 years ago

Read 2 more answers