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Shalnov [3]
2 years ago
6

Match each quadratic function given in factored form with its equivalent standard form listed on the left. f(x) = (x 2)(x – 6) f

(x) = (x – 4)(x 3) f(x) = (x – 12)(x 1) f(x) = (x – 3)(x 4)
Mathematics
1 answer:
aalyn [17]2 years ago
6 0

The standard form of the given quadratic functions in factored form are:

(x + 2)(x - 6) =  X² -4x - 12

(x – 4)(x + 3) = X² -x - 12

(x – 12)(x + 1) = X² - 11x - 12

(x – 3)(x + 4) = X² + x - 12

<h3>What are quadratic functions?</h3>

A quadratic function can be defined as a function having the highest degree 2. The standard form of a quadratic function is:

f(x) = ax²+bx+c

, where a and b are not equals zero.

To convert a factored quadratic function into the standard form, we first need to open the brackets by multiplying the integers. Then carry addition or subtraction operations to obtain the equation.

<h3>According to the given information:</h3>

We will begin with converting the first equation into standard form.

f(x)=(x+2)(x - 6)

f(x) = X² - 6x + 2x - 12

f(x) = X² -4x - 12

Similarly the standard forms for equation 2, 3, and 4 are:

f(x) = (x – 4)(x + 3)

     = X² -x - 12

f(x) = (x – 12)(x + 1)

     = X² - 11x - 12

f(x) = (x – 3)(x + 4)

    =  X² + x - 12

The standard form of the given quadratic functions in factored form are:

(x + 2)(x - 6) =  X² -4x - 12

(x – 4)(x + 3) = X² -x - 12

(x – 12)(x + 1) = X² - 11x - 12

(x – 3)(x + 4) = X² + x - 12

To know more about quadratic functions visit:

brainly.com/question/27958964

#SPJ4

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Find , , and if and terminates in quadrant .
ioda

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

STEP - BY - STEP EXPLANATION

What to find?

• sin2x

,

• cos2x

,

• tan2x

Given:

tanx = 2/3 = opposite / adjacent

We need to first make a sketch of the given problem.

Let h be the hypotenuse.

We need to find sinx and cos x, but to find sinx and cosx, first determine the value of h.

Using the Pythagoras theorem;

hypotenuse² = opposite² + adjacent²

h² = 2² + 3²

h² = 4 + 9

h² =13

Take the square root of both-side of the equation.

h =√13

This implies that hypotenuse = √13

We can now proceed to find the values of ainx and cosx.

Using the trigonometric ratio;

\sin x=\frac{opposite}{\text{hypotenuse}}=\frac{2}{\sqrt[]{13}}\cos x=\frac{adjacent}{\text{hypotenuse}}=\frac{3}{\sqrt[]{13}}

And we know that tanx =2/3

From the trigonometric identity;

sin 2x = 2sinxcosx

Substitute the value of sinx , cosx and then simplify.

\sin 2x=2(\frac{2}{\sqrt[]{13}})(\frac{3}{\sqrt[]{13}})=\frac{12}{13}

Hence, sin2x = 12/13

cos2x = cos²x - sin²x

Substitute the value of cosx, sinx and simplify.

\begin{gathered} \cos 2x=(\frac{3}{\sqrt[]{13}})^2-(\frac{2}{\sqrt[]{13}})^2 \\  \\ =\frac{9}{13}-\frac{4}{13} \\ =\frac{5}{13} \end{gathered}

Hence, cos2x = 5/13

tan2x = 2tanx / 1- tan²x

\tan 2x=\frac{2\tan x}{1-\tan ^2x}=\frac{2(\frac{2}{3})}{1-(\frac{2}{3})^2}=\frac{\frac{4}{3}}{1-\frac{4}{9}}=\frac{\frac{4}{3}}{\frac{9-4}{9}}=\frac{\frac{4}{3}}{\frac{5}{9}}=\frac{4}{3}\times\frac{9}{5}=\frac{4}{1}\times\frac{3}{5}=\frac{12}{5}

OR

\tan 2x=\frac{\sin 2x}{\cos 2x}=\frac{\frac{12}{13}}{\frac{5}{13}}=\frac{12}{5}

Hence, tan2x = 12/5

Therefore,

sin2x =12/13

cos2x = 5/13

tan2x = 12/5

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