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Ugo [173]
2 years ago
11

PLEASE HELP ME!!! What is the value of x? Enter your answer in the box. x =

Mathematics
1 answer:
Vaselesa [24]2 years ago
5 0

Your answer What is the value of x, you didn't specify

Value of x is used to consider unknown value. The letter “x” is commonly used in algebra to indicate an unknown value. It is referred to as a “variable” or, in some cases, a “unknown.” In x + 2 = 7, x is a variable. ... A variable need not be “x,” but might be “y,” "w," or any other letter, name, or symbol.

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The length of a rectangle is 6 yards longer than its width. If the perimeter of the rectangle is 32 yd, find its area in square
ddd [48]
Let, width = x
Length = x + 6

Now, perimeter, 2(l+b) = 2(x+6+x)
2(2x+6) = 32
4x + 12 = 32
4x = 20
x = 5 &
x+6 = 5+6 = 11

As rectangle's dimensions are 11*5, it's area would be: 11 * 5 = 55 yards²

So, your final answer is 55 Yd²

Hope this helps!
8 0
3 years ago
Please help me i need the answer
Amiraneli [1.4K]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
The pentagon shown could be reflected over which line to be carried onto itself?
Svetach [21]

Answer:

paraell

Step-by-step explanation:

3 0
3 years ago
WILL MARK BRAINLIEST FEELING LAZY WORTH 15 POINTS
Zinaida [17]

The irrational numbers are: √8, √10 and √15

Step-by-step explanation:

A rational number is a number that can be written in the form p/q where p&q are integers and q≠0.

"All the numbers whose square root is not a whole number and has an infinite number of digits after decimal, are irrational numbers"

So in the given options

\sqrt{4} = 2

Which can be written in the required form so √4 is a rational number

\sqrt{8}=2.828427124746190097603.....

√8 has an infinite expansion hence it cannot be written in the p/q form, so it is an irrational number

\sqrt{10}=3.16227766016837933....

√10 has an infinite expansion hence it cannot be written in the p/q form, so it is an irrational number

\sqrt{15}=3.87298334620.....

√15 has an infinite expansion hence it cannot be written in the p/q form, so it is an irrational number

\sqrt{36} = 6

Which can be written in the required form so √36 is a rational number

Hence,

The irrational numbers are: √8, √10 and √15

Keywords: Rational numbers, Irrational numbers

Learn more about rational numbers at:

  • brainly.com/question/3375830
  • brainly.com/question/3398261

#LearnwithBrainly

4 0
3 years ago
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