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3 years ago

Please help I will give you a decent about of points

Mathematics

2 answers:

dangina [55]3 years ago

7 0

Answer:

I also agree with the above answer. Please give me a clearer image..

Problem: Image quality

guapka [62]3 years ago

3 0

can you take a little more of a clearer picture please so I can help you

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What do I do with the x squared

Alexxandr [17]

first, find the square root of 45. and make x normal. a square root cancels out a square. It should be 6.7x

4 0

3 years ago

the ratio of goats to sheep at a university research farm is 4: 7. The number of sheep at the arm is 28. what is the number of g

GalinKa [24]

4+7=11 i.e. The whole.
7/11=28

1/11=4
Goats are 4/11 therefore
4 x 4= Ans
All the animals add up to 44 and if you check w/ 7/11 it is correct.

4 0

3 years ago

Help I will be marking brainliest!!

lora16 [44]

Answer:

<u>Given</u>: base = 10.4ft, height = 12.5

Area of octagon = 8(1/2 × b × h)

8(1/2 × 10.4 × 12.5)
520ft²

Volume of pool = 520ft² × 3ft

1560ft³

Now, 1 cubic ft takes 7.5 gallons to fill.

Therefore, 1560 cubic ft takes,

1560 × 7.5
11700

So, <u>Correct choice</u> - [D] 11,700.

5 0

3 years ago

In A School Election 3/4 Of The Students Vote. There Are 1464 Ballots. Write And Solve An Equation To Find The Number Of Student

klasskru [66]

A simple way to turn this into an equation is by replacing the words with letters:
1464B = 3/4 S

Then you have to remove the 3/4 from the right side of the equation. You can do this by dividing both sides by 3/4:
1464 / 3/4 = S

Then you have to do the sum:
1464
/ 3
= 0488

488
X 4
= 1952

There are 1952 students.

4 0

3 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

6 0

3 years ago