What is the volume of this square pyramid?<br> Enter your answer in the box.<br> ___

Twelve cans of peaches are placed into each box. Write a function rule for the number of boxes needed for c cans. How many boxes

Mars2501 [29]

C = # of cans

b = # of boxes

C | B

12 | 1

24 | 2

36 | 3

12b = C

12b/12 = 1440/12

b = 120 boxes

for 1440 cans.

6 0

2 years ago

A center for medical services reported that there were 295,000 appeals for hospitalization and other services. For this group, 4

pshichka [43]

Answer:

a) 0.0025 = 0.25% probability that none of the appeals will be successful.

b) 0.0207 = 2.07% probability that exactly one of the appeals will be successful.

c) 0.9768 = 97.68% probability that at least two of the appeals will be successful

Step-by-step explanation:

For each appeal, there are only two possible outcomes. Either it is succesful, or it is not. The probability of an appeal being succesful is independent of other appeals, so we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

45% of first-round appeals were successful.

This means that $p = 0.45$

Suppose 10 first-round appeals have just been received by a Medicare appeals office.

This means that $n = 10$

(a) Compute the probability that none of the appeals will be successful.

This is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.45)^{0}.(0.55)^{10} = 0.0025$

0.0025 = 0.25% probability that none of the appeals will be successful.

(b) Compute the probability that exactly one of the appeals will be successful.

This is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{10,1}.(0.45)^{1}.(0.55)^{9} = 0.0207$

0.0207 = 2.07% probability that exactly one of the appeals will be successful.

(c) What is the probability that at least two of the appeals will be successful

This is $P(X \geq 2)$

Either less than two appeals are succesful, or at least two are. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0025 + 0.0207 = 0.0232$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.0232 = 0.9768$

0.9768 = 97.68% probability that at least two of the appeals will be successful

6 0

2 years ago

The amount of sports drink in a cooler during practice is modeled by the equation

Alex777 [14]

Answer:

10

Step-by-step explanation:

8 0

2 years ago

In the diagram the quadrilateral

Y_Kistochka [10]

Answer:

x = 2 ; y = 3

Step-by-step explanation:

3x = 6

x = 2

4y = 12

y = 3

4 0

3 years ago

What must be included in a algebraic expression?

damaskus [11]

Answer:

Variable (or coefficients)

Step-by-step explanation:

4 0

3 years ago

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What is the volume of this square pyramid? Enter your answer in the box. ____ cm^3