Help asap pleaseeeee

Lena found the greatest common factor (GCF) of 24ab2c3 and 30a2b3c2 to be 6abc2 by using these steps: Step 1: GCF of 24 and 30 i

nataly862011 [7]

It is NOT the highest power shared BUT the lowest power shared. Step 2

7 0

3 years ago

Which equation is in standard form?

IgorC [24]

The standard form of an equation of a line:

Ax + By = C

Therefore your answer is:

8 0

3 years ago

Read 2 more answers

PLEASE HELP, I’LL GIVE BRAINLIST!

Alekssandra [29.7K]

Answer:

your answer would be 4/12 because there are 4 red marbles and 12 marbles total

Step-by-step explanation:

6 0

3 years ago

Find the cubic equations with the given roots. 1) 1,-3, and 5

MariettaO [177]

Ax3 + bx2 + cx + d = 0 where a 6= 0 All cubic equations have either one real root, or three real roots.

7 0

3 years ago

Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best po

mina [271]

Answer:

(a) The point estimate for the population proportion p is 0.34.

(b) The margin of error for the 99% confidence interval of population proportion p is 0.055.

(c) The 99% confidence interval of population proportion p is (0.285, 0.395).

Step-by-step explanation:

A point estimate of a parameter (population) is a distinct value used for the estimation the parameter (population). For instance, the sample mean $\bar x$ is a point estimate of the population mean μ.

Similarly, the the point estimate of the population proportion of a characteristic, p is the sample proportion $\hat p$ .

The (1 - α)% confidence interval for the population proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The margin of error for this interval is:

$MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

The information provided is:

$\hat p=0.34\\n=500\\(1-\alpha)\%=99\%$

(a)

Compute the point estimate for the population proportion p as follows:

Point estimate of p = $\hat p$ = 0.34

Thus, the point estimate for the population proportion p is 0.34.

(b)

The critical value of z for 99% confidence level is:

$z={\alpha/2}=z_{0.01/2}=z_{0.005}=2.58$

*Use a z-table for the value.

Compute the margin of error for the 99% confidence interval of population proportion p as follows:

$MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=2.58\sqrt{\frac{0.34(1-0.34)}{500}}$

$=2.58\times 0.0212\\=0.055$

Thus, the margin of error for the 99% confidence interval of population proportion p is 0.055.

(c)

Compute the 99% confidence interval of population proportion p as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$CI=\hat p\pm MOE$

$=0.34\pm 0.055\\=(0.285, 0.395)$

Thus, the 99% confidence interval of population proportion p is (0.285, 0.395).

6 0

3 years ago