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xenn [34]
3 years ago
8

If you steal the points, ill report you (❁*ᵕ*)︻╦╤─

Mathematics
2 answers:
lutik1710 [3]3 years ago
8 0

Answer:

(GIVING BRAINLIEST!!)

yeah yeah.

Step-by-step explanation:

Serga [27]3 years ago
4 0
From what I can tell it's B
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Johnny makes $8.25 an hour working at the local restaurant. His paycheck shows that he works 29.5 hours over the past week. How
svetlana [45]

To do this you can do (pay) x (hours) to work out how much Johnny makes for example:

8.25 x 29.5 = 243.375$ so the answer is 243.375$

4 0
3 years ago
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If a basketball was dropped 32 feet from a second floor of a home, how far would it rebound if it bounciness was
valentina_108 [34]

Answer:

23.68

Step-by-step explanation:

74% = 74/100

\frac{74}{100} · \frac{32}{1} = 23.68

4 0
3 years ago
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A family has two cars. The first car has a fuel efficiency of 40 miles per gallon of gas and the second has a fuel efficiency of
lesya692 [45]

Answer:

first car = 35, second car= 15

Step-by-step explanation:

40x+15y=1625

x+y=50

multiplying the 2nd by -15 and add the 2 equations, we get x= 35 and by substituting on second equation we get y= 15

4 0
2 years ago
Given a right triangle with a hypotenuse of 6 cm and a leg of 4cm, what is the measure of the other leg of the triangle rounded
slega [8]

Answer:

4.5 cm=L2

Step-by-step explanation:

This problem can be solved using the pythagorian theoreme:

H=\sqrt{L1^{2}+L2^{2}  }

Where:

H=6 cm

L1=4 cm

L2=?

We isolate our incognita an we get:

\sqrt{H^{2}-L1^{2}} =L2

We supplant with the given data:

\sqrt{(6cm)^{2}-(4cm)^{2}} =L2

\sqrt{36cm^{2}-16cm^{2}} =L2

\sqrt{36cm^{2}-16cm^{2}} =L2

\sqrt{20cm^{2}} =L2

4.5 cm=L2

5 0
3 years ago
Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor
docker41 [41]

Given:

The table of values is

Number of Students   :  7    14   21    28

Number of Textbooks : 35  70  105  140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

\dfrac{35}{7}=5

\dfrac{70}{14}=5

\dfrac{105}{21}=5

\dfrac{140}{28}=5

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

\dfrac{y}{x}=k

Here, k=5.

\dfrac{y}{x}=5

y=5x

Hence the rate of change is constant that is 5.

8 0
3 years ago
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