Answer:
The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

90% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).
Angle A = arctan(12/5) = 67.4 degrees
Angle A = arccos(5/13) = 67.4 degrees
yes the answer was the same
Answer:
14x-19
Step-by-step explanation: Now can someone answer my question look at my page
The answer to your question is = 148.06