Pls help, I'll make the brainliest person the first to answer pls

Determine a solution to system of linear inequalities graphed and justify your answer.

muminat

The last option. The lines graphed never touch so there is no solution

7 0

2 years ago

A certain group of students, the probability of a randomly chosen students is being male is 40%, the probability of the students

kumpel [21]

<h3>Answer:</h3>

$\large\boxed{A).\,10\%}$

<h3>Step-by-step explanation:</h3>

In this question, we're trying to find the probability of a male that also studies Spanish.

In this case, we know that:

There's a 40% chance of a student being a male
Probability of a male that studies Spanish is 25%

With the information above, we can find the probability.

To find the probability, we would need to find how much of 40 is 25%.

To do this, we would multiply 0.4 (40%) by 0.25 (25%) to find our probability.

Solve:

$0.4 *0.25=0.1\\\\\text{Move the decimal places two times to the right}\\\text{to turn it into a percent}\\\\\boxed{10\%}$

The probability of a male that studies Spanish is 10%

Your answer would be A). 10%

<h3>I hope this helped you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>

4 0

3 years ago

Find the shortest distance from<br> A to B in the diagram below.

vitfil [10]

Shortest distance = Displacement

And please provide the diagram

Must click thanks and mark brainliest

3 0

3 years ago

Complete the real-world problem that can be represented by 2x − 145 = 380.

belka [17]

262.5 is the solve for x

5 0

2 years ago

Read 2 more answers

A researcher is interested in religious differences for immigration checkpoint experiences at airports. Polling a sample of 340

vekshin1

Answer:

$z=\frac{0.52-0.46}{\sqrt{0.49(1-0.49)(\frac{1}{340}+\frac{1}{190})}}=1.325$

$p_v =2*P(Z>1.325)= 0.185$

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that we have a significant difference between the two proportions of negative experiences at 1% of significance.

Step-by-step explanation:

Data given and notation

$n_{M}=340$ sample of Muslims

$n_{C}=190$ sample of Christians

$p_{M}=0.52$ represent the proportion of Muslims with negative experience

$p_{C}=0.46$ represent the proportion of christians with negative experience

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

$\alpha=0.01$ significance level given

Concepts and formulas to use

We need to conduct a hypothesis in order to check if is there is a difference in the two proportions, the system of hypothesis would be:

Null hypothesis: $p_{M} - p_{C}=0$

Alternative hypothesis: $p_{M} - p_{C} \neq 0$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{M}-p_{C}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{M}}+\frac{1}{n_{C}})}}$ (1)

Where $\hat p=\frac{p_{M}+p_{C}}{2}=\frac{0.52+0.46}{2}=0.49$

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.52-0.46}{\sqrt{0.49(1-0.49)(\frac{1}{340}+\frac{1}{190})}}=1.325$

Statistical decision

Since is a two sided test the p value would be:

$p_v =2*P(Z>1.325)= 0.185$

Comparing the p value with the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that we have a significant difference between the two proportions of negative experiences at 1% of significance.

3 0

3 years ago