Factor each of the trinomials into 2 binomials 1. x^2+2x-15 2. 3x^2-11x+6

Mathematics

1 answer:

tresset_1 [31]2 years ago

6 0

Answer:

1.) (x-3)(x+5)

2.) (3x-2)(x-3)

Step-by-step explanation:

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Read 2 more answers

What is the solution of x=2+ square root x-2?

alex41 [277]

So I'm going to assume that this question is asking for non extraneous solutions, or solutions that are found in the equation and are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

$x-2=\sqrt{x-2}$

Next, square both sides:

$(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2$

Next, subtract x and add 2 to both sides of the equation:

$x^2-5x+6=0$

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

$x^2-2x-3x+6=0$