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zloy xaker [14]
2 years ago
6

The fuel tank of a certain airplane can hold up to gallons of fuel. Let be the total weight of the airplane (in pounds). Let be

the total amount of fuel in its tank (in gallons). Suppose that gives as a function of .
Mathematics
1 answer:
zloy xaker [14]2 years ago
3 0
A reasonable function is W = 7F + 5000


Where W is the weight of the plane and F is the number of gallons of fuel.


The domain is the set of possible values for F. That is from 0 (empty tank) to 400 (full tank).


So the domain is F = [0,400], or what is equivalente 0 ≤ F ≤ 400.


The range is the set of values of W.


The minimum value of W is when F = 0 => W = 7(0) + 5000 = 5,000.


The maximum value of W is when F = 400 => W = 7(400) + 5000 = 7,800


So the range is W = [5,000 ; 7,800], pr 5000 ≤ W ≤ 7,800.
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Option C will have greatest number of permutations.

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A.

The number of license plates with 4 letters followed by 3 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

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B.

The number of license plates with 3 letters followed by 4 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

So total options for 3 letters= 26*25*24 = 15600

Now, 4 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

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C. The number of license plates with 4 letters followed by 3 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 4 letters and 10 options for each 3 numbers

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total options for 4 letters and 3 numbers will be: 456,976,000

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The number of license plates with 3 letters followed by 4 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 3 letters and 10 options for each 4 numbers

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total options for 3 letters and 4 numbers will be: 175,760,000

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