Covers the 'point-slope' form of linear equations, including how to find a line ... For this one, they give you a point (x1, y1) and a slope m, and have you plug it into this ... You can use the Mat way widget below to practice finding a line equation .... Find the equation of the line that passes through the points (–2, 4) and (1, 2)
The option are missing in the question. The options are :
A. P = 2, a = 1
B. 
C. 
D. P = 2, a = 3
Solution :
The given function is 
So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.
When the four option being substituted in the function, we get
A). It is a constant function since 
B). Here, the value of a is a fraction which is less than 1, so it is a decay function. 
C). It is a constant function since the value of a is 1.
D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.

Therefore, option (D). represents an exponential function.
Answer:
sorry
Step-by-step explanation:
Shh shah ahahaiaia suasion
M=[(y2-y1)/(x2-x1)]
Sub in your points,
m=[(6)-(6)]/(4)-(-3)]
m=(0/7)
Which means that the slope is 0!