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3 years ago

Which point is a solution to the system of equations? y = 3x +4 y =+2

Mathematics

2 answers:

Papessa [141]3 years ago

7 0

(-2,3,2) is the answrr

Andru [333]3 years ago

3 0

(-2/3, 2)

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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How do you answer 3000(1+7%)×3

Nikitich [7]

3000(1.07)×3= 9,630.

8 0

3 years ago

Melissa is stacking storage cubes in a crate the bottom of the crate is 8 inches by 12 inches. The volume of the crate is 768 cu

Karo-lina-s [1.5K]

Answer:

12 cubes can fit in the create.

Step-by-step explanation:

We know that the volume of a the crate is 768 in³, and the definition of the volume is:

$V=A*h$

Where:

V is the volume
A is the area (A=8*12 in²)
h is the height

So $h=\frac{V}{A}=\frac{768}{12*8}=8 in$

Now, we know that the storage cube has a length of 4 in so we have a volume equal to 64 in³. Therefore we just need to divide 768 in³ by 64 in³ it is 12.

Finally, 12 cubes can fit in the create.

I hope it helps you!

3 0

3 years ago

Read 2 more answers

At a local pool club they advocate having 1 lifeguard for every 50 people.

kifflom [539]

C

Hope I helped! :-)

~Sequoyah! :-)

5 0

3 years ago

Who do you solve 36×14usingpartial products by using 2-digit by 2-digit help

topjm [15]

first you would do this

4x6=24

then,4x30=120

then,10x30=300

then 10x6=60 lastly you would add them up and get a sum of 504

6 0

3 years ago

Determine the first four terms of the sequence in which the nth term is

Licemer1 [7]

Answer:

The correct answer option is: $\frac{1}{3} ,\frac{1}{4} ,\frac{1}{5} ,\frac{1}{6}$ .

Step-by-step explanation:

We know that the $nth$ term $a_n$ for an arithmetic sequence is given by:

$a_n=\frac{(n+1)!}{(n+2)!}$

where $n$ is the number of the position of the term.

We are supposed to find the first four terms of the sequence so we will substitute the values of $n$ from 1 to 4 in the given formula to get:

1st term:

$a_1=\frac{(1+1)!}{(1+2)!}=\frac{1}{3}$

2nd term:

$a_2=\frac{(2+1)!}{(2+2)!}=\frac{1}{4}$

3rd term:

$a_3=\frac{(3+1)!}{(3+2)!}=\frac{1}{5}$

4th term:

$a_4=\frac{(4+1)!}{(4+2)!}=\frac{1}{6}$

8 0

3 years ago