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LekaFEV [45]
3 years ago
9

Which point is a solution to the system of equations? y = 3x +4 y =+2

Mathematics
2 answers:
Papessa [141]3 years ago
7 0
(-2,3,2) is the answrr
Andru [333]3 years ago
3 0
(-2/3, 2)


Solve for the first variable in one of the equations, then substitute the result into the other equation.
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
BRAINLIEST BRAINLIEST BRAINLIEST PLEASE ANDSER IT IS TIMED THANK YOU SO MUCCH
Doss [256]

Answer:

x=-b/2a

Step-by-step explanation:

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8 0
3 years ago
The total amount paid on a 35 year loan was $98,000. If the interest rate was 4.1% and compounded monthly, what was the principa
Levart [38]

Answer:

The principal amount was $23,393.45

Step-by-step explanation:

The total amount paid on a 35 year loan was $98,000 at the rate of interest 4.1%

We will calculate Principal amount by this formula

A=P(1+\frac{r}{n})^{nt}

Where A = amount (98,000)

           P = Principal amount (P)

           r = rate of interest 4.1% (0.041)

           n = number of compounding interest monthly (12)

           t = time (35 years)

98,000=P(1+\frac{0.041}{12})^{(12)(35)}

98,000=P(1+0.003416)^{(420)}

98,000=P(1.003416)^{(420)}

98,000 = P(4.189386)

= 4.189386P = 98,000

P = \frac{98000}{4.189386}

P = 23,392.4494 ≈ $23,392.45

The principal amount was $23,393.45

5 0
3 years ago
Read 2 more answers
How much will it cost to borrow $2,500 for a year at a simple interest rate at 14% please explain
Mariana [72]
Principle (P) = $ 2,500

Rate (R) = 14%

Time (T) = 1 year

Simple Interest (SI) = \frac{PRT}{100}

SI = \frac{2500 * 14 * 1}{100} =  \frac{25 *14}{1} = 350

Hence, the answer is $350.
3 0
3 years ago
In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th
olya-2409 [2.1K]

Answer:

\frac{BE}{EC} =\frac{1}{3}

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

\frac{BK}{CK} =\frac{1}{4}

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE                ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE     ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK  and Δ EBK are similar

so we have

\frac{AD}{BE} =\frac{DK}{BK}

\frac{AD}{BE} =\frac{4}{1}

\frac{BC}{BE}=\frac{4}{1}     ( ABCD is parallelogram so AD=BC)

\frac{BE+EC}{BE}=\frac{4}{1}         ( BC= BE+EC)

\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}

1+\frac{EC}{BE}=4

\frac{EC}{BE}=3  ( subtracting 1 from both side )

\frac{EC}{BE}=\frac{3}{1}

taking reciprocal both side

\frac{BE}{EC} =\frac{1}{3}


8 0
3 years ago
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