Answer:
The TAB key
Explanation:
Sam would use the TAB key, located on the left side of the keyboard, to move around his document to add stops and format its information properly.
Pressing the TAB key will introduce a tab code in his document, which is like moving ahead by a certain number of spaces (5,6, 10 spaces for example, depending on the configuration of the document), but without using spaces, using a tab which is a much better option to position, align things up.
Answer:
binary search will still be faster
Explanation:
Based on this scenario, the most likely result is that the binary search will still be faster. This is because Binary search repeatedly cuts the list in half thus shortening the search times drastically. This being said, the longer lists will still take more than 10 times as long than the shorter lists because there is a far greater list of combinations for the search algorithm's to sort through.
Answer:
The answer is "1".
Explanation:
The value of the count variable after the code snippet execution is 1 because we're using three in the array list, instead, take one of these for a loop of 0 to the array list size but now the ArrayList size is 3, as well as the loop size, operates from 0 to 2:
In the index =0:
We get somenum.get(index)=somenum.get(0)=1%2 not 0, so we go on to the next index.
Index: = 1
We get a somenum.get(index) =somenum.get(1) = two percent 2 comparable to 0, so the count variable is increased to 1 and switch to just the following index.
count=1
Index: = 2
They have a somenum.get(index) = somenum.get(2)=1 percent 2 not equivalent to 0.
Index= 3:
The index =3 <somenum.size()=3.
It isn't valid, and the loop breaks out and prints out the value of a count variable which is 1. so this becomes 3 < 3.
