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finlep [7]
2 years ago
6

Solve for x ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

Mathematics
1 answer:
dezoksy [38]2 years ago
4 0

Answer:

8

Step-by-step explanation:

Your equation would be 8x - 4 = 60.

So,

8x - 4 = 60

   + 4    + 4

8x = 64

/8     /8

x = 8

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Write the equation in slope-intercept form of a line that has a slope of 1/3 and passes through the point (-6, 0).
Vesna [10]

Answer: y = 1/3x +2

Step-by-step explanation:

The equation of line in slope - point form is given as:

y - y_{1} = m ( x - x_{1} )

m = 1/3

y_{1} = 0

x_{1} = -6

substituting into the formula , we have

y - 0 = 1/3 ( x - {-6} )

y = 1/3 (x+6)

y = 1/3x +2

5 0
3 years ago
Read 2 more answers
Which of the following decimals is equivalent to three and ten hundredths
Montano1993 [528]

Answer: 3.1 or 3.10

Step-by-step explanation:

3 and 10 hundredths = 3 + 10/100 = 3 + 0.10

3.10 / 3.1

6 0
2 years ago
identify the amplitude and period of the function then graph the function and describe the graph of G as a transformation of the
mrs_skeptik [129]

Given the function:

g(x)=cos4x

Let's find the amplitude and period of the function.

Apply the general cosine function:

f(x)=Acos(bx+c)+d

Where A is the amplitude.

Comparing both functions, we have:

A = 1

b = 4

Hence, we have:

Amplitude, A = 1

To find the period, we have:

\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}

Therefore, the period is = π/2

The graph of the function is shown below:

The parent function of the given function is:

f(x)=cosx

Let's describe the transformation..

Apply the transformation rules for function.

We have:

The transformation that occured from f(x) = cosx to g(x) = cos4x using the rules of transformation can be said to be a horizontal compression.

ANSWER:

Amplitude = 1

Period = π/2

Transformation = horizontal compression.

8 0
1 year ago
Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v
k0ka [10]

I'll use subscript notation for brevity, i.e. \frac{\partial f}{\partial x}=f_x.

By the chain rule,

z_u=z_xx_u+z_yy_u

z_v=z_xx_v+z_yy_v

z_w=z_xx_w+z_yy_w

We have

z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}

and

\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}

When u=1,v=1,w=0, we have

\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}

and the partial derivatives take on values of

\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}

So we end up with

\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}

3 0
3 years ago
I need some help please
klio [65]
True, because the dilation factor is less than one. This will result in the shape reducing.
4 0
3 years ago
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