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eimsori [14]
2 years ago
13

Okay very important question.

Mathematics
1 answer:
lapo4ka [179]2 years ago
4 0

Answer: It depends on how you put it in the calculator

Step-by-step explanation:

11x10=110

110-12=98

93/3 = 32.66

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3 years ago
Please answer this correctly
Oksana_A [137]

Answer:

1/9

Step-by-step explanation:

The answer is 1/9 because we already know the only even number on the spinner is 8.  We have a 1/3 chance on landing on 8.  Then it says we have to land on 7.  There is also a 1/3 chance for landing on 7.  So from this information, we do (1/3)*(1/3)=1/9

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Plot the point first and then use the slope from that point<br> (-4,3) M=-1/2
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Plot the point first and then use the slope from that point<span> - 3270801. ... </span>Plot the point first and then use the slope from that point (-4,3<span>) </span>M=-1/2<span>. 0</span>
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3 years ago
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tankabanditka [31]

Answer:

I think the equation that best represent the relationship between r and s is A. s=1/6r

3 0
3 years ago
2. When a large truckload of mangoes arrives at a packing plant, a random sample of 150 is selected and examined for
kirza4 [7]

a) The 90% confidence interval of the percentage of all mangoes on the truck that fail to meet the standards is: (7.55%, 12.45%).

b) The margin of error is: 2.45%.

c) The 90% confidence is the level of confidence that the true population percentage is in the interval.

d) The needed sample size is: 271.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions has the bounds given by the rule presented as follows:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The variables are listed as follows:

  • \pi is the sample proportion, which is also the estimate of the parameter.
  • z is the critical value.
  • n is the sample size.

The confidence level is of 90%, hence the critical value z is the value of Z that has a p-value of \frac{1+0.90}{2} = 0.95, so the critical value is z = 1.645.

The sample size and the estimate are given as follows:

n = 150, \pi = \frac{15}{150} = 0.1

The margin of error is of:

M = z\sqrt{\frac{0.1(0.9)}{150}} = 0.0245 = 2.45\%

The interval is given by the estimate plus/minus the margin of error, hence:

  • The lower bound is: 10 - 2.45 = 7.55%.
  • The upper bound is: 10 + 2.45 = 12.45%.

For a margin of error of 3% = 0.03, the needed sample size is obtained as follows:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.645\sqrt{\frac{0.1(0.9)}{n}}

0.03\sqrt{n} = 1.645\sqrt{0.1(0.9)}

\sqrt{n} = \frac{1.645\sqrt{0.1(0.9)}}{0.03}

(\sqrt{n}})^2 = \left(\frac{1.645\sqrt{0.1(0.9)}}{0.03}\right)^2

n = 271 (rounded up).

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

3 0
1 year ago
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