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2 years ago

Line A has a slope of 4. Line B has a slope of 1/4.

Mathematics

2 answers:

schepotkina [342]2 years ago

6 0

The correct answer is actually (a) because rate of change is x/y (or that's how I learned it) then the more big the slope the bigger the rate of change

marishachu [46]2 years ago

6 0

Line A is correct because the rule is rise over run and since the rise is 4 and run 1, the answer is 4.

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3 years ago

Jessie is fencing in a rectangular plot outside of her back door so that she can let her dogs out to play. She has 60 feet of fe

DerKrebs [107]

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Dimensions are length 15 feet and width 30 feet.

Maximum area of the plot is 450 feet².

Step-by-step explanation:

Let the length of the plot = x feet and width = y feet.

Since, the amount of fencing to be applied on the three sides of the plot is 60 feet.

We have,

$2x + y = 60$ i.e. $y=60-2x$

Now, Area of the rectangular plot = Length × Width

i.e. Area of the rectangular plot = $x \times y$

i.e. Area of the rectangular plot = $x\times (60-2x)$

i.e. Area of the rectangular plot = $-2x^2+60x$

<em>Since, the maximum of the quadratic equation $ax^2+bx+c$ will be obtained at $x= \frac{-b}{2a}$ .</em>

Then, the maximum of the area of the plot is at the point $x= \frac{-60}{2\times (-2)}$ i.e. x= 15

Then, maximum area of the rectangular plot = $-2x^2+60x$

i.e. maximum area of the rectangular plot = $-2\times 15^2+60\times 15$

i.e. maximum area of the rectangular plot = -450+900 = 450 feet²

Hence, Maximum area of the plot is 450 feet².

Then, $y=60-2\times 15$ implies $y=60-30$ i.e. y= 30.

Hence, the maximum area is enclosed by the length 15 feet and width 30 feet.

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3 years ago