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dangina [55]
3 years ago
6

COINS The Susan B. Anthony dollar coin has a hendecagon (11-gom) inscribed in a circle in its design. Each edge of the hendecago

n is
approximately 746 millimeters. What is the area of this regular polygon? Round to the nearest hundredth
Mathematics
1 answer:
Natalija [7]3 years ago
8 0

Answer:

700 or 0.76

Step-by-step explanation:

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A number sentence is shown below: 32 and 1 over 4Division sign1 over 8 equals 258
Sindrei [870]
Part A.

32'1/4÷1/8=258

1 team has 8 people, we currently have 32'1/4 teams, so how many people do we have? We have 258 people.

you can adjust this any way you want. you can say. if we have 258 people, we can make 32'1/4 teams of 8 people. and so on...

Part B.

32'1/4(teams)×8(people per team)=258 people

Part C.

you can explain this from what I said in Part A and Part B.

but 32'1/4 is 1/8 of 258
7 0
3 years ago
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A rectangular cardboard has dimensions as shown. The length of the cardboard can be found by dividing its area by its width. Wha
Annette [7]

Answer:

45678

Step-by-step explanation:

A rectangular cardboard has dimensions as shown. The length of the cardboard can be found by dividing its area by its width. What is the length of the cardboard in inches?

Rectangle with width labeled on the right, width equals 4 and 1 over 4 inches. Below the rectangle, it says, length equals question mark. Inside the rectangle, it says, area equals 41 and 2 over 3 square inches.

9 and 41 over 51

10 and 1 over 4

36 and 5 over 6

174 and 29 over 48

help asap

8 0
3 years ago
I need help again please help
makvit [3.9K]

1 out 12 is the probability of it being raspberry-filled.

3 0
3 years ago
There are a total of 66 students in the
attashe74 [19]

Answer:

A = 26

Step-by-step explanation:

sum of students = classA + classB + classC

let's say classA = A, classB = B, and classC = C

A + B + C = 66

class A has five more students than class B, so A = 5 more than B so A = 5+B

class C has 2 less students than class B, so C = 2 less than class B = B -2, so C = B-2

A + B + C = 66

A = 5+B

C = B-2

substitute 5+B for A and B-2 for C in the first equation to limit this to one variable (B)

(5+B) + B + (B-2) = 66

3B + 3 = 66

subtract 3 from both sides to isolate the variable and its coefficient

3B = 63

divide both sides by 3 to solve for B
B = 21

A = 5 + B = 5 + 21 = 26

7 0
2 years ago
Please tell me the answer! I'm crying in confusion! :(
Inessa [10]
First, change the fractions to a common denominator, which is 21. 

so 3/7 * 3/3  = 9/21

1/3 * 7/7 = 7/21

Add the two together

9/21 + 7/21 = 16/21

Then take 21/21 - 16/21 = 5/21

There is 5/21 of the pizza left.
6 0
3 years ago
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