Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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The answer to your question is A but i dont see a D option so it might be wrong
Answer:
its D Q and O
Step-by-step explanation:
Given:
The garden is a right triangle with base 10m and height 15m.
To draw:
The garden such that 1 unit on the grid below represents 2 m.
Solution:
We have,
1 unit = 2 m
So,
1 m = 0.5 units
Using this conversion, we get
10 m = 5 units
15 m = 7.5 units
Therefore, the base garden on the grid is 5 units and height is 7.5 units as shown below.
It’s 6 because the full length is 12 and it’s asking for the half of it