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amm1812
3 years ago
7

Given: QR I PT and ZQPR = ZSTR

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0

Answer:

\triangle PQR \sim \triangle TSR

Step-by-step explanation:

Given :

QR⊥PT

\angle QPR = \angle STR

To Prove : \triangle PQR \sim \triangle TSR

Solution:

Statements                                            Reasons

QR⊥PT                                                Given

∠QRP and ∠SRT are right angles       Def of perpendicular

∠QPR≅∠STR                                     Given

∠QRP = ∠SRT                                    All right angles are equal

ΔPQR≈ΔTSR                                     AA similarity

Hence  \triangle PQR \sim \triangle TSR

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Determine if Ginny factored correctly. If not, explain where she made an error. Ginny made a mistake in step 1 when she identifi
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Quadratic equations are second-order equations. Ginney made a mistake when she identified b = 31. It should be b = –31.

<h3>What is a Quadratic Equation?</h3>

A quadratic equation is an equation that can be written in the form of

ax²+bx+c.

Where a is the leading coefficient, and

c is the constant.

In order to find the mistake that Ginny made, we will first find the factors ourselves, therefore, we will factorize the trinomial,

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As we can see that the value of constants are,

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b = -31

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6x^2 - 31x -30 = 0\\\\6x^2 - 36x+5x -30 = 0\\\\6x(x-6)+5(x-6)=0\\\\(6x+5)(x-6)=0

Therefore, the factors of the trinomial 6x^2 - 31x -30 = 0 are (6x+5) and (x-6).

If we compare our process with Ginny's process, we will find that she has taken the value of the constant b as 31 which is wrong.

Hence, Ginney made a mistake when she identified b = 31. It should be b = –31.

Learn more about Quadratic Equation:

brainly.com/question/17177510

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