Answer/Step-by-step explanation:
Use equation y = mx+b
m is the slope and in the place for m is 15
b is the y intercept and because there is no y-int. it would be 0
Since the y-int is 0 then it is proportional.
This would be a positive slope.
Hope this helps :)
Since the degree of this polynomial is 5, there will be 5 possible zeros. To find the possible rational 0s, use the rational root theorem (p/q). P is the last, non x value, which here it is the four on the end. The q is the leading coefficient, which is also q. Next, find all of the factors of q and p, which since they are both 4, are ±1, ±2, and ±4. Next do all possible values of p/q, which are ±1, ±2, ±4, ±1/2, and ±1/4. These are all your possible rational zeros. complex 0s only come in pairs, so the maximum there can be is 4 complex zeros, meaning there is at least one rational, real 0. (i graphed it it is -1/2, so all others must be rational or imaginary)
Divide 4 by both sides
Then you get 4=3+b2
Then subtracts 3 from four
You get 1=b2
Answer:
40
Step-by-step explanation:
Also, you find it by multiplying.
Answer:
<em>octagon</em>
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<em>it </em><em>has </em><em>eight</em><em> </em><em>side</em>
<em>hope</em><em> it</em><em> helps</em>
