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Nutka1998 [239]
3 years ago
9

What is the solution to x 4 – 12x 2 + 10 > 0?

Mathematics
1 answer:
Umnica [9.8K]3 years ago
5 0

Answer: The picture contains the answer and the steps

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Fred and Matt are playing basketball. If x represents the points Matt ended with, and 3x represents the points Fred ended with,
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It tells you that Fred has three times the score more than Matt.

This is because Matt has x points, Fred tops Matt by 3x points.

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Simplify (-5) + (-2) - (-7) - (+9)
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-5-2+7-9 = -9

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Gary has a box of pencils. In the box, 7/21 of the pencils have been sharpened. Select the three fractions that are proportional
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Step-by-step explanation:

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Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

7/10 of 4/9(red coin from box A)

6/10 of 5/9(blue coin from box A). So

P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

Blue chip transferred, red coin chosen:

6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

5 0
3 years ago
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