Question

What is the diameter of a sphere with a volume of 170 m to the third, to the nearest tenth of a

Answer 1

Let radius be r

$\\ \sf\longmapsto V=170$

$\\ \sf\longmapsto \dfrac{4}{3}\pi r^3=170$

$\\ \sf\longmapsto \pi r^3=170(3/4)=127.5$

$\\ \sf\longmapsto r^3=127.5/\pi=127.5\div 3.14$

$\\ \sf\longmapsto r^3=40.6$

$\\ \sf\longmapsto r=\sqrt[3]{40.6}$

$\\ \sf\longmapsto r=3.3m$

• Diameter=2r=2(3.3)=6.6m

Answer 2

Answer:

The diameter of sphere = 6.6

Step-by-step explanation:

Let the radius of sphere = r

volume of sphere = 4/3 πr³ = 170

= πr³=170

= πr³=170(3/4)

= r³ = 127.5/π

= r³ = 127.5/3.14

= r³ = 40.6

= r = ³√40.6

= r= 3.3

so , the diameter is 2× radius

= 2(3.3) => 6.6